Q1Multiple choice
Using the number line, write the integer which is:
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Correct option: A
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Worked solution
(a)
Hence, 8
(b) 
Hence, 0
(c)
Hence, -4
(d)
Hence, -5
NCERT · Class 6 · Maths
Chapter 6: Integers
Practice each question, then open the answer or worked solution.
Exercise 6.2
Textbook page 128 · 5 questionsQ2Written answer
Use a number line and add the following integers.
(a) 9 + (–6)
(b) 5 + (–11)
(c) (–1) + (–7)
(d) (–5) + 10
(e) (–1) + (–2) + (–3)
(f) (–2) + 8 + (–4)
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Worked solution
(a)
Hence, 3
(b)
Hence, -6
(c)
Hence, -8
(d)
Hence, 5
(e)
Hence, -6
(f)
Hence, 2
Q3Written answer
Add without using a number line.
(a) 11 + (–7)
(b) (–13) + (+18)
(c) (–10) + (+19)
(d) (–250) + (+150)
(e) (–380) + (–270)
(f) (–217) + (–100)
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Worked solution
(a) 11 + (-7) = 4
(b) (-13) + (+18) = 5
(c) (-10) + (+19) = 9
(d) (-250) + (+150) = -100
(e) (-380) + (-270) = -650
(f) (-217) + (-100) = -317
Q4Written answer
Find the sum of:
(a) 137 and – 354
(b) – 52 and 52
(c) – 312, 39 and 192
(d) – 50, – 200 and 300
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Worked solution
(a) 137 and -354
(137) + (-354) = (137) + (-137) + (-217)
= 0 + (-217) [(137) + (-137) = 0]
= (-217)
= -217
(b) -52 and 52
(-52) + (+52) = 0 [(-a) + (+a) = 0]
(c) -312, 39 and 192
(-312) + (+39) + (+192) = (-231) + (-81) + (+39) + (+192)
= (-231) + (-81) + (+231)
= (-231) + (+231) + (-81)
= 0 + (-81) [(-a) + (+a) = 0]
= -81
(d) -50, -200 and 300
(-50) + (-200) + (+300) = (-50) + (-200) + (+200) + (+100)
= (-50) + 0 + (+100) [(-a) + (+a) = 0]
= (-50) + (+100)
= (-50) + (+50) + (+50)
= 0 + (+50) [(-a) + (+a) = 0]
= 50
Q5Written answer
Find the sum.
(a) (–7) + (–9) + 4 + 16
(b) (37) + (–2) + (–65) + (–8)
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Worked solution
(a) (-7) + (-9) + 4 + 16
= (-7) + (-9) + 4 + (+7) + (+9)
= (-7) + (+7) + (-9) + (+9) + 4
= 0 + 0 + 4 [(-a) + (+a) = 0]
= 4
(b) (37) + (-2) + (-65) + (-8)
= (+37) + (-75)
= (+37) + (-37) + (-38)
= 0 + (-38) [(-a) + (+a) = 0]
= -38