Evaluate
(i) 8!
(ii) 4! – 3!
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(i) Consider 8!
We know that 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
= 40320
(ii) Consider 4!-3!
4!-3! = (4 × 3!) – 3!
Above equation can be written as
= 3! (4-1)
= 3 × 2 × 1 × 3
= 18
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Practice each question, then open the answer or worked solution.
Evaluate
(i) 8!
(ii) 4! – 3!
(i) Consider 8!
We know that 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
= 40320
(ii) Consider 4!-3!
4!-3! = (4 × 3!) – 3!
Above equation can be written as
= 3! (4-1)
= 3 × 2 × 1 × 3
= 18
Is 3! + 4! = 7!?
Consider LHS 3! + 4!
Computing left hand side, we get
3! + 4! = (3 × 2 × 1) + (4 × 3 × 2 × 1)
= 6 + 24
= 30
Again considering RHS and computing, we get
7! = 7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040
Therefore LHS ≠ RHS
Therefore 3! + 4! ≠ 7!
Compute


If
find x.

Evaluate
,
When
(i) n = 6, r = 2
(ii) n = 9, r = 5

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