Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Differentiation - Calculus - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
Every graph below is calculated only from this selection.
Year-wise coverage for Differentiation. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| VITEEE 2025 | 2025 | 1 | View paper |
| WB JEE 2025 | 2025 | 2 | View paper |
| WB JEE 2024 | 2024 | 2 | View paper |
| WB JEE 2023 | 2023 | 6 | View paper |
| WB JEE 2022 | 2022 | 1 | View paper |
| WB JEE 2021 | 2021 | 2 | View paper |
| WB JEE 2020 | 2020 | 1 | View paper |
| WB JEE 2019 | 2019 | 4 | View paper |
| WB JEE 2018 | 2018 | 2 | View paper |
| WB JEE 2017 | 2017 | 2 | View paper |
| WB JEE 2011 | 2011 | 7 | View paper |
| WB JEE 2009 | 2009 | 2 | View paper |
| WB JEE 2008 | 2008 | 4 | View paper |
Practice every matching question in batches of 20, with every available option.
If \(y = {e^{{{\tan }^{ - 1}}x}}\), then
Suppose \(f:R \to R\) be given by \(f(x) = \left\{ \matrix{ 1,\,\,\,\,\,\,\,\,\,\,\mathrm{if}\,x = 1 \hfill \cr \[{e^{({x^{10}} - 1)}} + {(x - 1)^2}\sin {1 \over {x - 1}},\,\mathrm{if}\,x \ne 1 \hfill \cr} \right.\)\]
then
If \(y = {\log ^n}x\), where \({\log ^n}\) means \({\log _e}{\log _e}{\log _e}\,...\) (repeated n times), then \(x\log x{\log ^2}x{\log ^3}x\,.....\,{\log ^{n - 1}}x{\log ^n}x{{dy} \over {dx}}\) is equal to
Let \({\cos ^{ - 1}}\left( {{y \over b}} \right) = {\log _e}{\left( {{x \over n}} \right)^n}\), then \(A{y_2} + B{y_1} + Cy = 0\) is possible for, where \({y_2} = {{{d^2}y} \over {d{x^2}}},{y_1} = {{dy} \over {dx}}\)
Let \(f(x) = {x^m}\), m being a non-negative integer. The value of m so that the equality \(f'(a + b) = f'(a) + f'(b)\) is valid for all a, b > 0 is
The function \(y = {e^{kx}}\) satisfies \(\left( {{{{d^2}y} \over {d{x^2}}} + {{dy} \over {dx}}} \right)\left( {{{dy} \over {dx}} - y} \right) = y{{dy} \over {dx}}\). It is valid for
If \(x = \sin \theta\) and \(y = \sin k\theta\), then \((1 - {x^2}){y_2} - x{y_1} - \alpha y = 0\), for \(\alpha=\)
$$\text { If } y=\tan ^{-1}\left[\frac{\log _e\left(\frac{e}{x^2}\right)}{\log _e\left(e x^2\right)}\right]+\tan ^{-1}\left[\frac{3+2 \log _e x}{1-6 \cdot \log _e x}\right] \text {, then } \frac{d^2 y}{d x^2}=$$
If \(\mathrm{U}_{\mathrm{n}}(\mathrm{n}=1,2)\) denotes the \(\mathrm{n}^{\text {th }}\) derivative \((\mathrm{n}=1,2)\) of \(\mathrm{U}(x)=\frac{\mathrm{L} x+\mathrm{M}}{x^2-2 \mathrm{~B} x+\mathrm{C}}\) (L, M, B, C are constants), then \(\mathrm{PU}_2+\mathrm{QU}_1+\mathrm{RU}=0\), holds for
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