WB JEE 2009
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Find the values of a for which the expression \({x^2} - (3a - 1)x + 2{a^2} + 2a - 11\) is always positive.
The equations to the pairs of opposite sides of a parallelogram are x2 \(-\) 5x + 6 = 0 and y2 \(-\) 6y + 5 = 0. Find the equations of its diagonals.
Show that \({{\sin \theta } \over {\cos 3\theta }} + {{\sin 3\theta } \over {\cos 9\theta }} + {{\sin 9\theta } \over {\cos 27\theta }} = {1 \over 2}(\tan 27\theta - \tan \theta )\)
If x = sin t, y = sin 2t, prove that \((1 - {x^2}){{{d^2}y} \over {d{x^2}}} - x{{dy} \over {dx}} + 4y = 0\)
Product of any r consecutive natural numbers is always divisible by
If a, b, c are G.P. (a > 1, b > 1, c > 1), then for any real number x (with x > 0, x \(\ne\) 1) logax, logbx, logcx are in