Area Under The Curves - Calculus - Mathematics Previous Year Questions

The area (in sq units) bounded by the curve $y=2 x-x^2$ and the line $y=-x$ is

Area of the region bounded by the curve $y=2-x-3 x^2$, the $X$-axis, the $Y$-axis and the line $x=-2$ is

The area (in sq units) of the region bounded by the circle $x^2+y^2=64$, positive $X$-axis and the line $y=\sqrt{3} x$ is

The area (in sq units) of the region bounded by the curve $y=|\sin 2 x|$ and the $X$-axis in $[0,2 \pi]$ is

The area (in square units) of the region enclosed between the parabola $y^2=2 x$ and the line $y=4 x-1$

If the area of the region bounded by $y=\cos x, y=\sin x$, $x=\pi / 4$ and $x=\pi$ is bisected by the line $x=a$, then $\sin \left(a+\frac{\pi}{4}\right)=$

The area (in sq. units) enclosed by the curves $y=2 x-x^2$ and $y=x^2-2 x-6$ is

The area (in sq. units) of the portion lying above the $X$-axis and enclosed between the curves $y^2=2 a x-x^2$ and $y^2=a x$ is

If the area lying in the first quadrant and bounded by the circle $x^2+y^2-4 x=0$, the parabola $y^2=x$ and the $X$-axis is $A$, then $6 A-9 \sqrt{3}=$

The area (in sq. units) bounded by the parabola $y=x^2+3$, the tangent to the parabola at $(3,12)$ and the coordinate axes and lying in the first quadrant is