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Practice Indefinite Integration - Calculus - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Indefinite Integration. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| TS EAMCET 2023 (Online) 12th May Morning Shift | 2023 | 6 | View paper |
| TS EAMCET 2023 ONLINE 12TH MAY EVENING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY EVENING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY MORNING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY EVENING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY MORNING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2022 (Online) 19th July Evening Shift | 2022 | 4 | View paper |
| TS EAMCET 2022 (Online) 19th July Morning Shift | 2022 | 4 | View paper |
| TS EAMCET 2022 (Online) 20th July Evening Shift | 2022 | 5 | View paper |
| TS EAMCET 2022 (Online) 20th July Morning Shift | 2022 | 5 | View paper |
| TS EAMCET 2022 ONLINE 18TH JULY EVENING SHIFT | 2022 | 4 | View paper |
| TS EAMCET 2022 ONLINE 18TH JULY MORNING SHIFT | 2022 | 5 | View paper |
| TS EAMCET 2020 (Online) 10th September Evening Shift | 2020 | 5 | View paper |
| TS EAMCET 2020 (Online) 10th September Morning Shift | 2020 | 5 | View paper |
Practice every matching question in batches of 20, with every available option.
$$\begin{aligned} & \text { If } \int \frac{(x+3)}{(x-1)^2(2 x-1)} d x \\ & =\frac{A}{x-1}+B \log (2 x-1)+C \log (x-1)+k, \text { then } A+B+C= \end{aligned}$$
Let $x \neq \frac{-3}{5}, \frac{2}{5}$, if $f\left(\frac{2 x+1}{5 x+3}\right)=x+2$, then $\int f(x) d x=$
If $\int \frac{1+\cos 8 x}{\tan 2 x-\cot 2 x} d x=f(x) \cdot \cos (g(x))+c$, then $f\left(\frac{1}{4}\right)+g\left(\frac{1}{4}\right)=$
If $\int e^x \cos x d x=\frac{e^x}{2}(\cos x+\sin x)$ and
$$\int \frac{\cos \left(\log \left(\frac{2 x+3}{3-2 x}\right)\right)}{(3-2 x)^2} d x=\frac{f(x)}{24}[\cos (g(x))+\sin (g(x))]+c$$
then $g(1)=$
If $x>0$ and $x \neq(2 n+1) \frac{\pi}{2}$, then $\int\left(x \sqrt{x}-e^{\log (\sec x \tan x)}+\frac{3 x^2-2 x+1}{x^2}\right) d x=$
Let $f(x)=\int \frac{2 x^3-3 x^2+4 x-5}{x^2} d x$ and $f(1)=1$. Then, $f(5)=$
If $\frac{x^2+3}{\left(x^2+1\right)\left(x^2+2\right)}=\frac{A x+B}{x^2+1}+\frac{C x+D}{x^2+2}$ then $A+B+C+D=$
If $\frac{x^2-3 x+2}{(x-4)(x-3)^2}=\frac{A}{x-4}+\frac{B}{x-3}+\frac{C}{(x-3)^2}$ then $A+B+C=$
$$\int(2 x-3) \sqrt{3 x+2} d x=$$
| List-I | List-II |
| 1. \(\int \frac{\mathrm{sin}^{2} x}{\mathrm{cos}^{4} x} d x\)\(\int \frac{\mathrm{sin}^{2} x}{\mathrm{cos}^{4} x} d x\)int(sin^(2)x)/(cos^(4)x)dx | A. \(\quad \frac{\mathrm{tan}^{2} x}{2} + \mathrm{ln} | \mathrm{cos} x | + C\)\(\quad \frac{\mathrm{tan}^{2} x}{2} + \mathrm{ln} | \mathrm{cos} x | + C\)quad(tan^(2)x)/(2)+ln |cos x|+C |
| 2. \(\int \frac{\mathrm{sin}^{4} x}{\mathrm{cos}^{2} x} d x\)\(\int \frac{\mathrm{sin}^{4} x}{\mathrm{cos}^{2} x} d x\)int(sin^(4)x)/(cos^(2)x)dx | B. \(\mathrm{cos} x + \mathrm{sec} x + C\)\(\mathrm{cos} x + \mathrm{sec} x + C\)cos x+sec x+C |
| 3. \(\int \frac{\mathrm{sin}^{3} x}{\mathrm{cos}^{2} x} d x\)\(\int \frac{\mathrm{sin}^{3} x}{\mathrm{cos}^{2} x} d x\)int(sin^(3)x)/(cos^(2)x)dx | C. \(\frac{\mathrm{tan}^{3} x}{3} + C\)\(\frac{\mathrm{tan}^{3} x}{3} + C\)(tan^(3)x)/(3)+C |
| 4. \(\int \frac{\mathrm{sin}^{3} x}{\mathrm{cos}^{3} x} d x\)\(\int \frac{\mathrm{sin}^{3} x}{\mathrm{cos}^{3} x} d x\)int(sin^(3)x)/(cos^(3)x)dx | D. \(\mathrm{tan} x + \frac{\mathrm{sin} 2 x}{4} - \frac{3 x}{2} + C\)\(\mathrm{tan} x + \frac{\mathrm{sin} 2 x}{4} - \frac{3 x}{2} + C\)tan x+(sin 2x)/(4)-(3x)/(2)+C |
| E. \(\mathrm{cos} x - \mathrm{sec} x + C\)\(\mathrm{cos} x - \mathrm{sec} x + C\)cos x-sec x+C |
If $\int x^4(\log x)^3 d x=x^5\left[A(\log x)^3\right]$ $\left.+B(\log x)^2+C \log x+D\right]+k$, then $A+B+C+5 D=$
If $\frac{x+1}{\left(x^2+1\right)(x-1)^2}=\frac{A x+B}{x^2+1}+\frac{C}{x-1}+\frac{D}{(x-1)^2}$, then $A+B+C+D=$
If $\int \frac{2 \sin 2 x-3 \cos x}{2 \sin ^2 x-3 \sin x+4} d x=f(x)+C$, where $C$ is the constant of integration, then $f\left(\frac{\pi}{2}\right)-f(0)=$
$\int \frac{1}{\left(x+\frac{2}{x}\right) \sqrt{x^4+4 x^2+3}} d x=$
If $\frac{3 \pi}{2} < x < \frac{5 \pi}{2}$ and $\int(\sqrt{1-\sin x}+\sqrt{1+\sin x}) d x=f(x)+C$, where $C$ is the constant of integration, then $f\left(\frac{\pi}{3}\right)-f(0)=$
$\int \frac{2 x+3}{\sqrt{3 x^2-2 x+1}} d x=$
$$\int \frac{1}{16-7 \sin ^2 x} d x=$$
$$\int \frac{1}{(x-2)\left(x^2+1\right)} d x=$$
$$\int \frac{\sec ^2 x}{(\sec x+\tan x)^2} d x=$$
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