Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Area Under The Curves - Calculus - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Area Under The Curves. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| TS EAMCET 2023 ONLINE 12TH MAY EVENING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY MORNING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY EVENING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY MORNING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2020 (Online) 10th September Evening Shift | 2020 | 1 | View paper |
| TS EAMCET 2020 (Online) 10th September Morning Shift | 2020 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
The area (in sq units) bounded by the curve $y=2 x-x^2$ and the line $y=-x$ is
Area of the region bounded by the curve $y=2-x-3 x^2$, the $X$-axis, the $Y$-axis and the line $x=-2$ is
The area (in sq units) of the region bounded by the circle $x^2+y^2=64$, positive $X$-axis and the line $y=\sqrt{3} x$ is
The area (in sq units) of the region bounded by the curve $y=|\sin 2 x|$ and the $X$-axis in $[0,2 \pi]$ is
The area (in square units) of the region enclosed between the parabola $y^2=2 x$ and the line $y=4 x-1$
If the area of the region bounded by $y=\cos x, y=\sin x$, $x=\pi / 4$ and $x=\pi$ is bisected by the line $x=a$, then $\sin \left(a+\frac{\pi}{4}\right)=$