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Practice Matrices And Determinants - Algebra - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Matrices And Determinants. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| TS EAMCET 2023 (Online) 12th May Morning Shift | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 12TH MAY EVENING SHIFT | 2023 | 5 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY EVENING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY MORNING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY EVENING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY MORNING SHIFT | 2023 | 4 | View paper |
| TS EAMCET 2022 (Online) 19th July Evening Shift | 2022 | 4 | View paper |
| TS EAMCET 2022 (Online) 19th July Morning Shift | 2022 | 5 | View paper |
| TS EAMCET 2022 (Online) 20th July Evening Shift | 2022 | 5 | View paper |
| TS EAMCET 2022 (Online) 20th July Morning Shift | 2022 | 4 | View paper |
| TS EAMCET 2022 ONLINE 18TH JULY EVENING SHIFT | 2022 | 5 | View paper |
| TS EAMCET 2022 ONLINE 18TH JULY MORNING SHIFT | 2022 | 4 | View paper |
| TS EAMCET 2020 (Online) 10th September Evening Shift | 2020 | 3 | View paper |
| TS EAMCET 2020 (Online) 10th September Morning Shift | 2020 | 3 | View paper |
Practice every matching question in batches of 20, with every available option.
If $A$ is a $3 \times 3$ matrix and $|A|=\frac{1}{2}$, then $\left|A^{-1}(\operatorname{Adj}(\operatorname{Adj} A))\right|^{-1}=$
If $\frac{x^2+7}{\left(x^2+1\right)(x-2)}=\frac{A}{x-2}+\frac{B x+C}{x^2+1}$, then the determinant of the matrix $\left[\begin{array}{ll}A & B \\ C & \frac{2}{5}\end{array}\right]$ is
If $A, P, B$ are $3 \times 3$ matrices. If $|-B|=5,\left|B A^T\right|=15$, $\left|P^T A P\right|=-27$, then one of the values of $|P|$ is
Let $x=\alpha, y=\beta, z=\gamma$ be the unique solution of the system of simultaneous linear equations $2 x+3 y-2 z+4=0,3 x-4 y+3 z+5=0$, $k x-2 y+z+3=0$. If $\alpha=-2$, then $k=$
If $A+B=\left[\begin{array}{lll}2 & 1 & 2 \\ 1 & 2 & 0 \\ 0 & 2 & 2\end{array}\right], A B=\left[\begin{array}{lll}1 & 2 & 2 \\ 1 & 1 & 0 \\ 1 & 2 & 1\end{array}\right]$, then $A^2+B(A+B)=$
$\left|\begin{array}{ccc}1 & 1 & 1 \\ a^2 & b^2 & c^2 \\ a^3 & b^3 & c^3\end{array}\right|=$
Let $\alpha, \beta, \gamma$ be real numbers. If $A=\left[\begin{array}{ccc}7 & 3 & \alpha \\ \beta & 1 & -11 \\ -5 & \gamma & 19\end{array}\right]$ is a $3 \times 3$ matrix satisfying $A\left[\begin{array}{c}5 \\ -13 \\ 11\end{array}\right]=\left[\begin{array}{c}-290 \\ -119 \\ 210\end{array}\right]$, then $(\operatorname{adj} A)^{-1}+\operatorname{adj} A^{-1}=$
If $[\alpha \beta \gamma]\left[\begin{array}{ccc}1 & 2 & 3 \\ 2 & 3 & -5\end{array}\right]=[352]$, then $\alpha^3+\beta^3+\gamma^3=$
$$\left|\begin{array}{ccc} \sqrt{3} & 2 \sqrt{5} & \sqrt{5} \\ \sqrt{15} & 5 & \sqrt{10} \\ 3 & \sqrt{15} & 5 \end{array}\right|=$$
If $A$ is a non-singular matrix such that $(A-2 I)$ $(A-3 I)=0$, then $\frac{1}{5} A+\frac{6}{5} A^{-1}=$
Let $A$ be a matrix such that $A B$ is a scalar matrix, where $B=\left[\begin{array}{ll}1 & 2 \\ 0 & 3\end{array}\right]$ and $\operatorname{det}(3 A)=27$. Then, $3 A^{-1}+A^2=$
$$\begin{aligned} &\text { If } \omega \neq 1 \text { is a cube root of unity, then }\\ &\left|\begin{array}{ccc} \omega+\omega^2 & \omega^2+\omega^9 & \omega^9+\omega \\ \omega^{27}+\omega^{31} & \omega^{31}+\omega^{17} & \omega^{17}+\omega^{27} \\ \omega^{30}+\omega^{41} & \omega^{41}+\omega^{19} & \omega^{19}+\omega^{30} \end{array}\right|= \end{aligned}$$
If $A$ is a symmetric matrix with real entries, then
If $A=\left[\begin{array}{lll}1 & a & 3 \\ b & 2 & c \\ 3 & d & 4\end{array}\right]$ is a symmetric matrix and $B=\left[\begin{array}{ccc}0 & 5 & b \\ -5 & 0 & -7 \\ 6 & c & 0\end{array}\right]$ is a skew-symmetric matrix, then $A B=$
If $x=\alpha, y=\beta, z=\gamma$ is the unique solution of the system of linear equations $2 x-3 y+5 z=12,5 x+2 y+3 z=11$ and $x+2 y-3 z=-3$, then $2 \alpha+5 \beta+3 \gamma=$
If the inverse of the matrix $A=\left[\begin{array}{ccc}-1 & -3 & -2 \\ 0 & 1 & 2 \\ 3 & 4 & 5\end{array}\right]$ is $A^{-1}=\left[\begin{array}{lll}a_1 & a_2 & a_3 \\ b_1 & b_2 & b_3 \\ c_1 & c_2 & c_3\end{array}\right]$, then $a_1+c_2+b_3=$
If $A=\left[\begin{array}{ccc}k & 5 & 2 \\ 2 & -k & 5 \\ 5 & 2 & -k\end{array}\right]$ and $\operatorname{det} A=190$, then $\operatorname{adj} A=$
If the unique solution of the simultaneous linear equations $3 x-2 y+z=5 k, 2 x+3 y-2 z=-5 k$, $x+4 y+3 z=k$ is $x=\alpha, y=\beta, z=3$, then $k=$
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