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Practice Chemical Kinetics - Physical Chemistry - Chemistry previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Chemical Kinetics. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| TS EAMCET 2023 (Online) 12th May Morning Shift | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 12TH MAY EVENING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY EVENING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 13TH MAY MORNING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY EVENING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2023 ONLINE 14TH MAY MORNING SHIFT | 2023 | 1 | View paper |
| TS EAMCET 2022 (Online) 19th July Evening Shift | 2022 | 1 | View paper |
| TS EAMCET 2022 (Online) 19th July Morning Shift | 2022 | 1 | View paper |
| TS EAMCET 2022 (Online) 20th July Evening Shift | 2022 | 1 | View paper |
| TS EAMCET 2022 (Online) 20th July Morning Shift | 2022 | 1 | View paper |
| TS EAMCET 2022 ONLINE 18TH JULY EVENING SHIFT | 2022 | 2 | View paper |
| TS EAMCET 2022 ONLINE 18TH JULY MORNING SHIFT | 2022 | 1 | View paper |
| TS EAMCET 2020 (Online) 10th September Evening Shift | 2020 | 1 | View paper |
| TS EAMCET 2020 (Online) 10th September Morning Shift | 2020 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
Half-life periods for a reaction at initial concentrations of 0.1 M and 0.01 M are 5 and 50 minutes, respectively. The order of reaction is
The rate constant of a reaction is increased by 4 times after addition of catalyst to the reaction mixture at the same temperature of $27^{\circ} \mathrm{C}$. The change in the activation energy of this reaction is (Take $\ln (1 / 4)=-1386, R=8.314$ )
If the definition of the temperature coefficient of the reaction holds good for a reaction between $27^{\circ} \mathrm{C}$ and $37^{\circ} \mathrm{C}$, the activation energy for the reaction in $\mathrm{kJ} \mathrm{mol}^{-1}$ is
The graph obtained between $\ln k$ ( $k=$ rate constant) on $y$-axis and $1 / T$ on $x$-axis is a straight line. The slope of it is $-4 \times 10^4 \mathrm{~K}$. The activation energy of the reaction (in $\left.\mathrm{kJ} \mathrm{mol}^{-1}\right)$ is $\left(R=831 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$
For a zero order reaction $A \rightarrow$ product, a plot of $[A]$ (on $y$-axis) and time (on $x$-axis) gave a straight line with slope equal to $-3 \times 10^{-3} \mathrm{M} \mathrm{min}^{-1}$ and intercept equal to $2 \times 10^{-2} \mathrm{M}$ (on y -axis). What is the rate constant (in M $\mathrm{min}^{-1}$ ) of this reaction?
The rate of a first order reaction doubles when the temperature changes from 300 K to 310 K . The activation energy of the reaction (in $\mathrm{kJ} \mathrm{mol}^{-1}$ ) is ( $R=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}, \log 2=0.3$ )
A possible mechanism for the gaseous reaction $2 \mathrm{H}_2+2 \mathrm{NO} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{N}_2$ is
Step 1:2 $\mathrm{NO} \rightleftharpoons \mathrm{N}_2 \mathrm{O}_2$
Step 2 : $\mathrm{N}_2 \mathrm{O}_2+\mathrm{H}_2 \longrightarrow \mathrm{~N}_2 \mathrm{O}+\mathrm{H}_2 \mathrm{O}$ (slow)
Step 3: $\mathrm{N}_2 \mathrm{O}+\mathrm{H}_2 \longrightarrow \mathrm{~N}_2+\mathrm{H}_2 \mathrm{O}$
The rate law for this reaction is
The rate law for the decomposition of hydrogen iodide is $-\frac{d[\mathrm{HI}]}{d t}=k[\mathrm{HI}]^2$. The units of rate constant $k$ are
The specific rate constant of decomposition of a compound is given by $\ln k=5.0-\frac{12000}{T}$. The activation energy of decomposition for this compound at 300 K is
For a zero order reaction, the plot of concentration of reactant vs time is (Hint: Consider the intercept on the concentration axis)
Which of the following is a zero order reaction?
The reaction, $2 A \rightarrow 2 B+C$ has a rate constant of $1.2 \times 10^{-2} \mathrm{~s}^{-1}$. Which of the following is correct?
For a reaction, the threshold energy is $75 \mathrm{~kJ} /$ mole. If the internal energy of the reactants is 20 $\mathrm{kJ} /$ mole, the activation energy (in $\mathrm{kJ} /$ mole) is
$$A \xrightarrow{\text { Catalyst } 1} P_1, k_1=1 \mathrm{~s}^{-1}$$
Reaction 2 :
$$A \xrightarrow{\text { Catalyst } 2} P_2, k_2=0.1 \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}$$
Reaction 3 :
$$A \xrightarrow{\text { Catalyst } 3} P_3, k_3=0.01 \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}$$
The correct relations between the rate of the reactions at 1 M of $A$ are