Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Inverse Trigonometric Functions - Trigonometry - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Inverse Trigonometric Functions. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
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Question coverage for the most populated papers. Every active PYP paper remains listed below.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| KCET 2026 | 2026 | 2 | View paper |
| KCET 2025 | 2025 | 2 | View paper |
| KCET 2024 | 2024 | 3 | View paper |
| KCET 2023 | 2023 | 2 | View paper |
| KCET 2022 | 2022 | 1 | View paper |
| KCET 2021 | 2021 | 2 | View paper |
| KCET 2020 | 2020 | 3 | View paper |
| KCET 2019 | 2019 | 3 | View paper |
| KCET 2018 | 2018 | 2 | View paper |
| KCET 2017 | 2017 | 2 | View paper |
Practice every matching question in batches of 20, with every available option.
$$\cos \left[2 \sin ^{-1} \frac{3}{4}+\cos ^{-1} \frac{3}{4}\right]=$$
If \(f(x)=\sin ^{-1}\left(\frac{2^{x+1}}{1+4^x}\right)\) then \(f^{\prime}(0)=\)
If \(a+\frac{\pi}{2}<2 \tan ^{-1} x+3 \cot ^{-1} x< b\) then '\(a\)' and '\(b\)' are respectively.
The value of \(\cos \left(\sin ^{-1} \frac{\pi}{3}+\cos ^{-1} \frac{\pi}{3}\right)\) is Does not exist
If \(f(x)=\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)\), then \(f^{\prime}(\sqrt{3})\) is
The domain of the function defined by \(f(x)=\cos ^{-1} \sqrt{x-1}\) is
\(\cos \left[\cot ^{-1}(-\sqrt{3})+\frac{\pi}{6}\right]\) is equal to
\(\tan ^{-1}\left[\frac{1}{\sqrt{3}} \sin \frac{5 \pi}{2}\right] \sin ^{-1}\left[\cos \left(\sin ^{-} \frac{\sqrt{3}}{2}\right)\right]\) is equal to
Domain \(\cos ^{-1}[x]\) is, where [ ] denotes a greatest integer function
The value of \(\cot ^{-1}\left[\frac{\sqrt{1-\sin x}+\sqrt{1+\sin x}}{\sqrt{1-\sin x}-\sqrt{1+\sin x}}\right]\), where \(x \in\left(0, \frac{\pi}{4}\right)\) is
If \(\sin ^{-1}\left(\frac{2 a}{1+a^2}\right)+\cos ^{-1}\left(\frac{1-a^2}{1+a^2}\right)=\tan ^{-1}\left(\frac{2 x}{1-x^2}\right)\) where \(a, x \in(0,1)\), then the value of \(x\) is
If $\cos ^{-1} x+\cos ^{-1} y+\cos ^{-1} z=3 \pi$, then $x(y+z)+y(z+x)+z(x+y)$ equals to
Let $f: R \rightarrow R$ be given $f(x)=\tan x$. Then, $f^{-1}(1)$ is
If $2 \sin ^{-1} x-3 \cos ^{-1} x=4, x \in[-1,1]$, then $2 \sin ^{-1} x+3 \cos ^{-1} x$ is equal to
$$\sec ^2\left(\tan ^{-1} 2\right)+\operatorname{cosec}^2\left(\cot ^{-1} 3\right)=$$
$2 \cos ^{-1} x=\sin ^{-1}\left(2 x \sqrt{1-x^2}\right)$ is valid for all values of ' $x$ ' satisfying
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