Circular Motion - Mechanics - Physics Previous Year Questions

When a car of mass \(m\) is moving with speed \(v\) along a circle of radius \(r\) on a level road, the centripetal force is provided by \(f\), where \(f\) denotes

(\(\mu_s\) \(\to\) coefficient of friction, N \(\to\) normal reaction)

A ball is moving in a circular path of radius \(5 \mathrm{~m}\). If tangential acceleration at any instant is \(10 \mathrm{~ms}^{-2}\) and the net acceleration makes an angle of \(30^{\circ}\) with the centripetal acceleration, then, the instantaneous speed is

A metal ball of \(20 \mathrm{~g}\) is projected at an angle \(30^{\circ}\) with the horizontal with an initial velocity \(10 \mathrm{~ms}^{-1}\). If the mass and angle of projection are doubled keeping the initial velocity the same, the ratio of the maximum height attained in the former to the latter case is :

A body is moving along a circular path of radius '\(r\)' with a frequency of revolution numerically equal to the radius of the circular path. What is the acceleration of the body if radius of the path is \(\left(\frac{5}{\pi}\right) m\) ?

One end of the string of length $l$ is connected to a particle of mass \(m\) and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed \(v\), the net force on the particle (directed towards centre) will be ( \(T\) represents the tension in the string)

A motor cyclist starts from the top of an inclined plane of height $h$ to go around a globe of death trap of radius $r$. The ratio of minimum height ' $h$ ' of the inclined plane to the radius ' $r$ ' of the death globe in order to go around the death globe successfully is