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Exam Details

Mining Engineering (MN) 2012

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Questions 65
Duration 180 mins
Package Mining Engineering (MN) - Previous Year Papers

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Difficulty distribution

Easy 65 100%

Question type distribution

Multiple Choices 65 100%

Instructions

Mining Engineering (MN) 2012 – Instructions
  • Total number of questions: 65
  • 30 questions carry one mark each
  • 35 questions carry two marks each
  • Negative marking: 1/3 of the marks allotted to the question
  • Use of calculator is allowed
  • This is a proctored examination
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Syllabus

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Sample questions from this paper

Questions are selected across the paper subjects wherever the paper contains that variety.

1
2012 · Unclassified
Mining Engineering (MN) 2012
Q.1 – Q.25 carry one mark each.

A 30 m steel tape having an area of cross-section of 5 x 10−6 m2 is standardized at 20°C, supported under a tension of 5.45 N. It is used to measure a horizontal distance of 81.15 m under an applied tension of 9.09 N. The error, due to incorrect pulling arrangement in this observation, in m is (Esteel = 200 GPa)

A
0.148
B
0.295
C
1.820
D
3.640
2
2012 · Unclassified
Mining Engineering (MN) 2012

The coefficient of variation of a dataset is measured by

A
mean
B
mean
C
standard deviation
D
variance
3
2012 · Unclassified
Mining Engineering (MN) 2012

The value of ∫01 sin−1(cos x) dx is

A
(π−1)/2
B
(π+1)/2
C
(2π+1)/2
D
2π
4
2012 · Unclassified
Mining Engineering (MN) 2012

Assuming sin(1) = 0.841 and sin(3) = 0.141, the Lagrangian linear interpolating polynomial, for the function f(x) = sin(x) defined on the interval [1, 3] and passing through the end points of the interval, is

A
−0.35x + 1.19
B
3.05x + 11.92
C
−35.00x + 119.10
D
−40.50x + 219.19
5
2012 · Unclassified
Mining Engineering (MN) 2012

If Poisson’s ratio of a rock sample is 0.25, then the relationship among the modulus of elasticity (E), modulus of rigidity (G) and bulk modulus (K) is

A
E = K = G
B
E > G > K
C
E = G > K
D
E > K > G
6
2012 · Unclassified
Mining Engineering (MN) 2012

The 2nd order differential equation having a solution y = (Ax)4 + B, where A and B are constants, is

A
d²y/dx² + 2/x dy/dx = 0
B
d²y/dx² + 2 dy/dx = 0
C
(d²y/dx²)² + 2 dy/dx = 0
D
d²y/dx² + dy/dx = 0