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Exam Details

LMRC AE Electrical Engineering 2015

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Questions 100
Duration 180 mins
Package AE & JE Exams - Previous Year Papers

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Difficulty distribution

Medium 66 66%
Easy 17 17%
Hard 17 17%

Question type distribution

Multiple Choices 100 100%

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Sample questions from this paper

Questions are selected across the paper subjects wherever the paper contains that variety.

1
2015 · Unclassified
LMRC AE Electrical Engineering 2015
For the circuit shown in the figure below, the switch has been in the position A for a long time. At t = 0, the switch has moved to B. Then, the capacitor voltage Vc for t > 0 is:
A
Vc (t) = (24 – 6e-2t) V
B
Vc (t) = (30 – 15e-0.5t) V
C
Vc (t) = (6 – 6-2t) V
D
Vc (t) = (30 – 5e-0.5t) V
2
2015 · Unclassified
LMRC AE Electrical Engineering 2015
For the circuit shown below, the natural frequencies at port 2 are given by s + 2 = 0 and s + 5 = 0, without knowing which refers to open circuit and which to short circuit. Then the impedances Z11 and Z22 are given respectively by:
A
B
C
D
3
2015 · Unclassified
LMRC AE Electrical Engineering 2015
The Y parameter of the network are:
A
B
C
D
4
2015 · Unclassified
LMRC AE Electrical Engineering 2015
Applying Norton’s Theorem, the Norton’s equivalent circuit to the left of the terminals “a” and “b” in the below circuit is having equivalent current source (IN) and equivalent resistance (RN)
A
5 Ampere, 4 Ohm
B
9 Ampere, 1.6 Ohm
C
4 Ampere, 3 Ohm
D
4 Ampere, 6 Ohm
5
2015 · Unclassified
LMRC AE Electrical Engineering 2015
For a perfect conductor, the field strength at a distance equal to the skin depth is X% of the field strength at its surface. The value X% is:
A
0
B
36
C
26
D
50
6
2015 · Unclassified
LMRC AE Electrical Engineering 2015
When the air pocket is trapped inside a dielectric of relative permittivity “5”, for a given applied voltage across the dielectric, the ratio of stress in the air pocket to that in the dielectric is equal to
A
2025-01-05 13:30:00
B
5
C
5 – 1
D
1 + 5