JEE MAIN 2023 ONLINE 8TH APRIL EVENING SHIFT
Review the key details, then start the test when you are ready. You can also open the full package to see related papers.
Paper pattern & analysis
Filter this paper by subject, topic or subtopic. Every graph updates from the selected questions.
Topic distribution
Subtopic distribution
Difficulty distribution
Question type distribution
Syllabus
Sample questions from this paper
Questions are selected across the paper subjects wherever the paper contains that variety.
Work done by a Carnot engine operating between temperatures \(127^{\circ} \mathrm{C}\) and \(27^{\circ} \mathrm{C}\) is \(2 \mathrm{~kJ}\). The amount of heat transferred to the engine by the reservoir is :
Arrange the following gases in increasing order of van der Waals constant 'a'
A. Ar
B. \(\mathrm{CH}_{4}\)
C. \(\mathrm{H}_{2} \mathrm{O}\)
D. \(\mathrm{C}_{6} \mathrm{H}_{6}\)
Choose the correct option from the following.
Let the vectors \(\vec{u}_{1}=\hat{i}+\hat{j}+a \hat{k}, \vec{u}_{2}=\hat{i}+b \hat{j}+\hat{k}\) and \(\vec{u}_{3}=c \hat{i}+\hat{j}+\hat{k}\) be coplanar. If the vectors \(\vec{v}_{1}=(a+b) \hat{i}+c \hat{j}+c \hat{k}, \vec{v}_{2}=a \hat{i}+(b+c) \hat{j}+a \hat{k}\) and \(\vec{v}_{3}=b \hat{i}+b \hat{j}+(c+a) \hat{k}\) are also coplanar, then \(6(\mathrm{a}+\mathrm{b}+\mathrm{c})\) is equal to :
For a given transistor amplifier circuit in \(\mathrm{CE}\) configuration \(\mathrm{V}_{\mathrm{CC}}=1 \mathrm{~V}, \mathrm{R}_{\mathrm{C}}=1 ~\mathrm{k} \Omega, \mathrm{R}_{\mathrm{b}}=100 ~\mathrm{k} \Omega\) and \(\beta=100\). Value of base current \(\mathrm{I}_{\mathrm{b}}\) is

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : Sodium is about 30 times as abundant as potassium in the oceans.
Reason R : Potassium is bigger in size than sodium.
In the light of the above statements, choose the correct answer from the options given below
Let \(\mathrm{a}_{\mathrm{n}}\) be the \(\mathrm{n}^{\text {th }}\) term of the series \(5+8+14+23+35+50+\ldots\) and \(\mathrm{S}_{\mathrm{n}}=\sum_\limits{k=1}^{n} a_{k}\). Then \(\mathrm{S}_{30}-a_{40}\) is equal to :