Exam Details
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
Review the key details, then start the test when you are ready. You can also open the full package to see related papers.
Questions
90
Duration
180 mins
Package
IIT-JEE Main - Previous Year Papers
Paper pattern & analysis
Filter this paper by subject, topic or subtopic. Every graph updates from the selected questions.
Topic distribution
Subtopic distribution
Difficulty distribution
90questions
Medium
53
58.9%
Easy
36
40%
Hard
1
1.1%
Question type distribution
90questions
Multiple Choices
90
100%
Syllabus
Full Syllabus
Sample questions from this paper
Questions are selected across the paper subjects wherever the paper contains that variety.
2019 · Physics · Modern Physics · Atoms And Nuclei
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
In a radioactive decay chain, the initial nucleus is \({}_{90}^{232}\)Th. At the end there are 6 \(\alpha\)-particles and 4 \(\beta\)-particles which are emitted. If the end nucleus is \({}_Z^A\)X, A and Z are given by :
2019 · Chemistry · Physical Chemistry · Surface Chemistry
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
Among the following the false statement is -
2019 · Mathematics · Algebra · Sequences And Series
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
If the sum of the first 15 terms of the series \({\left( {{3 \over 4}} \right)^3} + {\left( {1{1 \over 2}} \right)^3} + {\left( {2{1 \over 4}} \right)^3} + {3^3} + {\left( {3{3 \over 4}} \right)^3} + ....\) is equal to 225 k, then k
is equal to :
2019 · Physics · Modern Physics · Electronic Devices
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
In the figure, given that VBB supply can vary from 0 to 5.0 V, VCC = 5V, \(\beta\)dc = 200, RB = 100 k\(\Omega\), RC = 1 k\(\Omega\) and VBE = 1.0 V. The minimum base current and the input voltage at which the transistor will go to saturation, will be respectively :


2019 · Chemistry · Physical Chemistry · Gaseous State
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
An open vessel at 27oC is heated until two fifth of the air (assumed as an ideal gas) it has escaped from the vessel assuming that the volume of the vessel remains constant, the temperature at which the vessel has been
heated is -
2019 · Mathematics · Coordinate Geometry · Parabola
JEE MAIN 2019 ONLINE 12TH JANUARY EVENING SLOT
The equation of a tangent to the parabola, x2
= 8y, which makes an angle \(\theta\) with the positive directions of x-axis, is :