Exam Details
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
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Questions
90
Duration
180 mins
Package
IIT-JEE Main - Previous Year Papers
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Subtopic distribution
Difficulty distribution
90questions
Medium
63
70%
Easy
27
30%
Question type distribution
90questions
Multiple Choices
90
100%
Syllabus
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Sample questions from this paper
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2019 · Chemistry · Physical Chemistry · Surface Chemistry
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
The correct option among the following is :
2019 · Physics · Modern Physics · Atoms And Nuclei
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
Two radioactive substances A and B have decay constants 5\(\lambda\) and \(\lambda\) respectively. At t = 0, a sample has the
same number of the two nuclei. The time taken for the ratio of the number of nuclei to become \({\left( {{1 \over e}} \right)^2}\)
will be :
2019 · Mathematics · Algebra · Sequences And Series
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
The sum
\(1 + {{{1^3} + {2^3}} \over {1 + 2}} + {{{1^3} + {2^3} + {3^3}} \over {1 + 2 + 3}} + ...... + {{{1^3} + {2^3} + {3^3} + ... + {{15}^3}} \over {1 + 2 + 3 + ... + 15}}\)\(- {1 \over 2}\left( {1 + 2 + 3 + ... + 15} \right)\) is equal to :
\(1 + {{{1^3} + {2^3}} \over {1 + 2}} + {{{1^3} + {2^3} + {3^3}} \over {1 + 2 + 3}} + ...... + {{{1^3} + {2^3} + {3^3} + ... + {{15}^3}} \over {1 + 2 + 3 + ... + 15}}\)\(- {1 \over 2}\left( {1 + 2 + 3 + ... + 15} \right)\) is equal to :
2019 · Chemistry · Inorganic Chemistry · Isolation Of Elements
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
The correct statement is :
2019 · Physics · Mechanics · Waves
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
A source of sound S is moving with a velocity of 50 m/s towards a stationary observer. The observer
measures the frequency of the source as 1000 Hz. What will be the apparent frequency of the source when it
is moving away from the observer after crossing him? (Take velocity of sound in air is 350 m/s)
2019 · Mathematics · Algebra · 3D Geometry
JEE MAIN 2019 ONLINE 10TH APRIL EVENING SLOT
A perpendicular is drawn from a point on the line \({{x - 1} \over 2} = {{y + 1} \over { - 1}} = {z \over 1}\) to the plane x + y + z = 3 such that the
foot of the perpendicular Q also lies on the plane x – y + z = 3. Then the co-ordinates of Q are :