Exam Details
JEE ADVANCED 2019 PAPER 2 OFFLINE
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Questions
54
Duration
180 mins
Package
IIT-JEE Advance - Previous Year Papers
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Topic distribution
Subtopic distribution
Difficulty distribution
54questions
Medium
29
53.7%
Hard
18
33.3%
Easy
7
13%
Question type distribution
54questions
Multiple Choices
36
66.7%
Numerical Answer Type (NAT)
18
33.3%
Syllabus
Full Syllabus
Sample questions from this paper
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2019 · Mathematics · Algebra · Permutations And Combinations
JEE ADVANCED 2019 PAPER 2 OFFLINE
Let |X| denote the number of elements in a set X. Let S = {1, 2, 3, 4, 5, 6} be a sample space, where each element is equally likely to occur. If A and B are independent events associated with S, then the number of ordered pairs (A, B) such that 1 \(\le\) |B| < |A|, equals .............
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2019 · Physics · Mechanics · Motion
JEE ADVANCED 2019 PAPER 2 OFFLINE
A ball is thrown from ground at an angle \(\theta\) with horizontal and with an initial speed u0. For the resulting projectile motion, the magnitude of average velocity of the ball up to the point when it hits the ground for the first time is V1. After hitting the ground, the ball rebounds at the same angle \(\theta\) but with a reduced speed of \({{{u_0}} \over \alpha }\). Its motion continues for a long time as shown in figure. If the magnitude of average velocity of the ball for entire duration of motion is 0.8 V1, the value of \(\alpha\) is ..................
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2019 · Chemistry · Inorganic Chemistry · Coordination Compounds
JEE ADVANCED 2019 PAPER 2 OFFLINE
Total number of \(cis\,N - Mn - Cl\) bond angles (that is \(Mn - N\) and \(Mn - Cl\) bonds in cis positions) present in a molecule of \(cis[Mn{(en)_2}C{l_2}]\) complex is ..................
(en = NH2CH2CH2NH2)
(en = NH2CH2CH2NH2)
Enter a numerical response
2019 · Mathematics · Trigonometry · Inverse Trigonometric Functions
JEE ADVANCED 2019 PAPER 2 OFFLINE
The value of
$${\sec ^{ - 1}}\left( \matrix{ \[{1 \over 4}\sum\limits_{k = 0}^{10} {\sec \left( {{{7\pi } \over {12}} + {{k\pi } \over 2}} \right)}\] \sec \left( {{{7\pi } \over {12}} + {{(k + 1)\pi } \over 2}} \right) \hfill \cr} \right)$$
in the interval \(\left[ { - {\pi \over 4},\,{{3\pi } \over 4}} \right]\) equals ..........
$${\sec ^{ - 1}}\left( \matrix{ \[{1 \over 4}\sum\limits_{k = 0}^{10} {\sec \left( {{{7\pi } \over {12}} + {{k\pi } \over 2}} \right)}\] \sec \left( {{{7\pi } \over {12}} + {{(k + 1)\pi } \over 2}} \right) \hfill \cr} \right)$$
in the interval \(\left[ { - {\pi \over 4},\,{{3\pi } \over 4}} \right]\) equals ..........
Enter a numerical response
2019 · Physics · Electricity · Electromagnetic Induction
JEE ADVANCED 2019 PAPER 2 OFFLINE
A 10 cm long perfectly conducting wire PQ is moving with a velocity I cm/s on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor L = 1 mH and a resistance R = 1\(\Omega\) as shown in figure. The horizontal rails, L and R lie in the same plane with a uniform magnetic field B = 1 T perpendicular to the plane. If the key S is closed at certain instant, the current in the circuit after 1 millisecond is x \(\times\) 10-3 A, where the value of x is ...........
[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given e-1 = 0.37, where e is base of the natural logarithm]
[Assume the velocity of wire PQ remains constant (1 cm/s) after key S is closed. Given e-1 = 0.37, where e is base of the natural logarithm]
Enter a numerical response
2019 · Chemistry · Physical Chemistry · Chemical Kinetics And Nuclear Chemistry
JEE ADVANCED 2019 PAPER 2 OFFLINE
The decomposition reaction
$$2{N_2}{O_5}(g)\buildrel \Delta \over \longrightarrow 2{N_2}{O_4}(g) + {O_2}(g)$$
is started in a closed cylinder under isothermal isochoric condition at an initial pressure of 1 atm. After Y \(\times\) 103 s, the pressure inside the cylinder is found to be 1.45 atm. If the rate constant of the reaction is 5 \(\times\) 10-4s-1, assuming ideal gas behaviour, the value of Y is ...............
$$2{N_2}{O_5}(g)\buildrel \Delta \over \longrightarrow 2{N_2}{O_4}(g) + {O_2}(g)$$
is started in a closed cylinder under isothermal isochoric condition at an initial pressure of 1 atm. After Y \(\times\) 103 s, the pressure inside the cylinder is found to be 1.45 atm. If the rate constant of the reaction is 5 \(\times\) 10-4s-1, assuming ideal gas behaviour, the value of Y is ...............
Enter a numerical response