Exam Details
JEE ADVANCED 2015 PAPER 1 OFFLINE
Review the key details, then start the test when you are ready. You can also open the full package to see related papers.
Questions
60
Duration
180 mins
Package
IIT-JEE Advance - Previous Year Papers
Paper pattern & analysis
Filter this paper by subject, topic or subtopic. Every graph updates from the selected questions.
Topic distribution
Subtopic distribution
Difficulty distribution
60questions
Medium
36
60%
Hard
17
28.3%
Easy
7
11.7%
Question type distribution
60questions
Multiple Choices
36
60%
Numerical Answer Type (NAT)
24
40%
Syllabus
Full Syllabus
Sample questions from this paper
Questions are selected across the paper subjects wherever the paper contains that variety.
2015 · Physics · Mechanics · Heat And Thermodynamics
JEE ADVANCED 2015 PAPER 1 OFFLINE
Two spherical stars A and B emit blackbody radiation. The radius of A is 400 times that of B and A emits
104 times the power emitted from B. The ratio \(\left( {{{{\lambda _A}} \over {{\lambda _B}}}} \right)\) of their wavelengths \({{\lambda _A}}\) and \({{\lambda _B}}\) at which the peaks
occur in their respective radiation curves is
Enter a numerical response
2015 · Chemistry · Organic Chemistry · Basics Of Organic Chemistry
JEE ADVANCED 2015 PAPER 1 OFFLINE
The total number of stereoisomers that can exist for M is ___________.
Enter a numerical response
2015 · Mathematics · Trigonometry · Trigonometric Functions And Equations
JEE ADVANCED 2015 PAPER 1 OFFLINE
The number of distinct solutions of the equation
$${5 \over 4}{\cos ^2}\,2x + {\cos ^4}\,x + {\sin ^4}\,x + {\cos ^6}\,x + {\sin ^6}\,x\, = \,2$$
in the interval \(\left[ {0,\,2\pi } \right]\) is
$${5 \over 4}{\cos ^2}\,2x + {\cos ^4}\,x + {\sin ^4}\,x + {\cos ^6}\,x + {\sin ^6}\,x\, = \,2$$
in the interval \(\left[ {0,\,2\pi } \right]\) is
Enter a numerical response
2015 · Physics · Modern Physics · Atoms And Nuclei
JEE ADVANCED 2015 PAPER 1 OFFLINE
Consider a hydrogen atom with its electron in the nth orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of n is (hc = 1242 eV nm)
Enter a numerical response
2015 · Chemistry · Inorganic Chemistry · P Block Elements
JEE ADVANCED 2015 PAPER 1 OFFLINE
The number of lone pairs of electrons in N2O3 is ___________.
Enter a numerical response
2015 · Mathematics · Algebra · Probability
JEE ADVANCED 2015 PAPER 1 OFFLINE
The minimum number of times a fair coin needs to be tossed, so that the probability of getting at least two heads is at least \(0.96,\) is
Enter a numerical response