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NCERT Exemplar · Class 12 · Chemistry

Chapter 8: The D-block and F-block Elements

Practice each question, then open the answer or worked solution.

Exercise

21 questions
Q1Written answer

Electronic configuration of a transition element ${\text{X}}$ in +3 oxidation state is \[\left[ {Ar} \right] 3{d^5}\]. What is its atomic number?

(A) 25 

(B) 26 

(D) 27 

(D) 24

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Worked solution

Ans: (B) 26

Positive oxidation states indicate the loss of electrons from the atom. If X is in +3 oxidation state, then three electrons have been removed from it. Find the atomic number of the parent atom, we will add three in the given electronic number. i.e.

${{\text{X}}^{{\text{3 + }}}}{\text{(Z = 23)  =  }}\left[ {{\text{Ar}}} \right]{\text{ 3}}{{\text{d}}^{\text{5}}}$

${\text{X  =  23  +  3  =  26}}$ 


Q2Written answer

The electronic configuration of \[Cu\left( {II} \right)\] is \[3{d^9}\] whereas that of \[Cu\left( I \right)\] is \[3{d^{10}}\]. Which of the following is correct?

(a) \[Cu\left( {II} \right)\]  is more stable .

(b) \[Cu\left( {II} \right)\] is less stable

(c) \[Cu\left( I \right)\] and  \[Cu\left( {II} \right)\] are equally stable

(d) Stability of \[Cu\left( {II} \right)\] and \[Cu\left( I \right)\] depends on the nature of copper salts.

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Worked solution

Ans: (A) \[Cu\left( {II} \right)\] is more stable .

Electronic configuration of \[{\text{Cu}}\]is \[\left[ {{\text{Ar}}} \right]{\text{ 3}}{{\text{d}}^{{\text{10}}}}{\text{ 4}}{{\text{s}}^{\text{1}}}\]

\[{\text{Cu}}\left( {\text{I}} \right)\] - \[\left[ {{\text{Ar}}} \right]{\text{ 3}}{{\text{d}}^{{\text{10}}}}{\text{ 4}}{{\text{s}}^0}\]

\[{\text{Cu}}\left( {{\text{II}}} \right)\]- \[\left[ {{\text{Ar}}} \right]{\text{ 3}}{{\text{d}}^9}{\text{ 4}}{{\text{s}}^0}\]

Despite the fact that\[{\text{Cu}}\left( {\text{I}} \right)\]  has fully filled 3d-orbital but \[{\text{Cu}}\left( {{\text{II}}} \right)\] is more stable than \[{\text{Cu}}\left( {\text{I}} \right)\] due to the greater effective nuclear charge of \[{\text{Cu}}\left( {{\text{II}}} \right)\] as nucleus has to hold 17 electrons rather than 18 electrons like in \[{\text{Cu}}\left( {\text{I}} \right)\].


Q3Written answer

Metallic radii of some transition elements are given below. Which of these elements will have the highest density? 

Element

Fe

Co

Ni

Cu

Metallic radii/pm

126

125

125

128


  (A) Fe

  (B) Ni

  (C) Co

  (D) Cu 

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Worked solution

Ans: (D) Cu

Density is mass by volume. As we move from left to right for a long period, the atomic radii decrease. Hence, volume decreases. Also, an increase in atomic masses is observed. 

So overall the density increases out of the above option from iron to copper, copper will have the highest density.


Q4Written answer

Generally, transition elements form coloured salts due to the presence of unpaired electrons. Which of the following compounds will be coloured in solid-state?

(A) $A{g_2}S{O_4} $

(B) $Cu{F_2} $

(C) $Zn{F_2} $

(D) $C{u_2}C{l_2}$ 

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Worked solution

Ans: (B) $Cu{F_2} $

$\left( {\text{A}} \right){\text{ A}}{{\text{g}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{ (A}}{{\text{g}}^{\text{ + }}}) \to {\text{ 5}}{{\text{d}}^{{\text{10}}}}{\text{ 6}}{{\text{s}}^{\text{0}}}$

$\left( {\text{B}} \right){\text{ Cu}}{{\text{F}}_{\text{2}}}{\text{  (C}}{{\text{u}}^{{\text{2 + }}}}) \to {\text{ 3}}{{\text{d}}^9}{\text{ 4}}{{\text{s}}^{\text{0}}}$

$\left( {\text{C}} \right){\text{ Zn}}{{\text{F}}_{\text{2}}}{\text{ (Z}}{{\text{n}}^{{\text{2 + }}}}{\text{)}} \to {\text{ 3}}{{\text{d}}^{{\text{10}}}}{\text{ 4}}{{\text{s}}^{\text{0}}}$

$\left( {\text{D}} \right){\text{ C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}{\text{ (C}}{{\text{u}}^{\text{ + }}}) \to {\text{ 3}}{{\text{d}}^{{\text{10}}}}{\text{ 6}}{{\text{s}}^{\text{0}}}$

Unpaired electrons present in any compound impart colour to the salt of transition metal. Only \[{\text{Cu}}{{\text{F}}_{\text{2}}}\] has unpaired electrons in its \[{\text{3d}}\]orbital that’s why it is white coloured in its solid-state while rest of the salts are colourless.


Q5Written answer

In addition to a small amount of \[KMn{O_4}\] to concentrate \[{H_2}S{O_4}\], a green oily compound is obtained which is highly explosive in nature. Identify the compound from the following:

(A) $M{n_2}{O_7} $

(B) $Mn{O_2}$

(C) $MnS{O_4} $

(D) $M{n_2}{O_3}$ 

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Worked solution

Ans: (A)  $M{n_2}{O_7} $

${\text{2KMn}}{{\text{O}}_{\text{4}}}{\text{  +  2}}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{(conc}}{\text{.) }} \to {\text{ M}}{{\text{n}}_{\text{2}}}{{\text{O}}_{\text{7}}}{\text{    +    2KHS}}{{\text{O}}_{\text{4}}}{\text{  +  }}{{\text{H}}_{\text{2}}}{\text{O}}$

Manganese heptoxide is an acid anhydride of permanganic acid \[\left( {{\text{ HMn}}{{\text{O}}_{\text{4}}}} \right)\]. It is a dangerous oxidiser, volatile and highly reactive liquid.


Q6Written answer

The magnetic nature of elements depends on the presence of unpaired electrons. Identify the configuration of the transition element, which shows the highest magnetic moment.

(A) $3{d^7} $

(B) $3{d^5} $

(C) $3{d^8} $

(D) $3{d^2}$ 

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Worked solution

Ans: (B) $3{d^5} $

Magnetic moment of an electron/dipole moment is caused by its intrinsic properties of spin and electric charge. It depends upon the number of unpaired electrons in its valence shell. The more the number of unpaired electrons, the greater will be the value of magnetic moment.

${\text{3}}{{\text{d}}^{\text{7}}}{\text{  =  3 unpaired electrons }}$

${\text{3}}{{\text{d}}^{\text{5}}}{\text{  =  5 unpaired electrons}}$

${\text{3}}{{\text{d}}^{\text{8}}}{\text{  =  2 unpaired electrons }}$

${\text{3}}{{\text{d}}^{\text{2}}}{\text{  =   2 unpaired electrons}}$ 

Out of all, \[{\text{3}}{{\text{d}}^{\text{5}}}\] has five unpaired electrons that is maximum and hence it has the highest magnetic moment.


Q7Written answer

Which of the following oxidation states is common for all lanthanides?

(A) $ + 2 $

(B) $ + 3$

(C) $ + 4 $

(D) $ + 5$ 

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Ans: (B) +3

Out of all +3 is the most common oxidation state for all the lanthanide elements.


Q8Written answer

Which of the following reactions are disproportionation reactions?

i. $C{u^ + } \xrightarrow{{}}C{u^{2 + }}  +  Cu $

ii. $3Mn{O^{4-}}  +  4{H^ + } \xrightarrow{{}} 2Mn{O_4}^--  +  Mn{O_2}  +  2{H_2}O $

iii. $2KMn{O_4} \xrightarrow{{}} {K_2}Mn{O_4}  +  Mn{O_2}  +  {O_2} $

iv. $2Mn{O_4}^-  +  3M{n^{2 + }}  +  2{H_2}O \xrightarrow{{}} 5Mn{O_2}  +  4{H^ + }$ 

(A)i,ii

(B)i,ii,iii

(C)ii,iii,iv

(D) i,iv

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Ans: (A)i,ii

Disproportionation/redox reaction is a reaction in which one compound is oxidised as well as reduced at the same time.

$\left( {\text{A}} \right){\text{ C}}{{\text{u}}^{\text{ + }}}{\text{ }} \to {\text{ C}}{{\text{u}}^{{\text{2 + }}}}{\text{  +    Cu }}$

${\text{        ( + 1)       ( + 2)        (0) }}$

$\left( {\text{B}} \right){\text{ 3Mn}}{{\text{O}}^{{\text{4--}}}}{\text{  +  4}}{{\text{H}}^{\text{ + }}}{\text{ }} \to {\text{ 2Mn}}{{\text{O}}_{\text{4}}}^{\text{--}}{\text{  +  Mn}}{{\text{O}}_{\text{2}}}{\text{  +  2}}{{\text{H}}_{\text{2}}}{\text{O }}$

${\text{         ( + 6)                          ( + 7)           ( + 4)}}$ 


Q9Written answer

When \[KMn{O_4}\] solution is added to oxalic acid solution, the decolourisation is slow in the beginning but becomes instantaneous after some time because

(A) \[{\text{}}C{O_2}\] is formed as the product 

(B) Reaction is exothermic

(C) \[Mn{O_4}\] catalyses the reaction 

(D) \[M{n^{2 + }}\] acts as auto catalyst

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Ans: (D)\[M{n^{2 + }}\] acts as auto catalyst

\[{\text{M}}{{\text{n}}^{{\text{2 + }}}}\] formed in the reaction acts as an autocatalyst. Auto catalyst is a compound that is one of the products that are formed in the reaction itself catalyses the reaction.

Reaction: \[{\text{2Mn}}{{\text{O}}^{{\text{4 - }}}}{\text{  +  16}}{{\text{H}}^{\text{ + }}}{\text{ +  5}}{{\text{C}}_{\text{2}}}{{\text{O}}_{\text{4}}}^{{\text{2 - }}} \to {\text{ 2M}}{{\text{n}}^{{\text{2 + }}}}{\text{  +  10C}}{{\text{O}}_{\text{2}}}{\text{  +  8H2O}}\]


Q10Written answer

There are 14 elements in the actinide series. Which of the following elements does-not belong to this series?

(A) $ U $

(B) $ Np $

(C) $Tm $

(D) $ Fm$ 

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Ans: (C) $Tm $

In the periodic table, actinides lie from atomic number 90 to 103. 

Thulium is not an actinide; it is a lanthanide.