Chapter 8: The D-block and F-block Elements

Q52Written answer

Match the catalysts given in Column I with the processes given in Column II.

Column I	Column II
(i) Ni in the presence of hydrogen	(a) Ziegler Natta catalyst
(ii)\[ C{u_2}C{l_2}\]	(b) Contact process
(iii)\[{V_2}{O_5}\]	(c) Vegetable oil to ghee
(iv) Finely divided iron	(d) Sandmeyer reaction
(v)\[TiC{l_4} + Al{\left( {C{H_3}} \right)_3}\]	(e) Haber’s Process
	(f) Decomposition of \[KCl{O_3}\]

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Column I	Column II
(i) Ni in the presence of hydrogen	(c) Vegetable oil to ghee
(ii)\[{\text{ C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}{\text{}}\]	(d) Sandmeyer reaction
(iii)\[{{\text{V}}_{\text{2}}}{{\text{O}}_{\text{5}}}{\text{}}\]	(b) Contact process
(iv) Finely divided iron	(e) Haber’s Process
(v)\[{\text{TiC}}{{\text{l}}_{\text{4}}}{\text{ + Al}}{\left( {{\text{C}}{{\text{H}}_{\text{3}}}} \right)_{\text{3}}}{\text{}}\]	(a) Zieglar Natta catalyst

Q53Written answer

Match the compounds/elements given in Column I with uses given in Column II.

Column I (Compound/element)	Column II (Use)
(i) Lanthanoid oxide	(a) Production of iron alloy
(ii) Lanthanoid	(b) Television screen
(iii) Misch metal	(c) Petroleum cracking
(iv) Magnesium based alloy is constituent of	(d) Lanthanoid metal + iron
(v) Mixed oxides of lanthanides are employed	(e) Bullets
	(f) In X-ray screen

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Column I (Compound/element)	Column II (Use)
(i) Lanthanide oxide	(b) Television screen
(ii) Lanthanoid	(a) Production of iron alloy
(iii) Misch metal	(d) Lanthanoid metal + iron
(iv) Magnesium based alloy is constituent of	(e) Bullets
(v) Mixed oxides of lanthanoids are employed	(c) Petroleum cracking

Q54Written answer

Match the properties given in Column I with the metals given in Column II.

Column I (Property)	Column II (Metal)
(i) An element which can show +8 oxidation state	(a) Mn
(ii) 3d block element that can show upto +7 oxidation state	(b) Cr
(iii) 3d block element with highest melting point	(c) Os
	(d) Fe

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Column I (Property)	Column II (Metal)
(i) An element which can show +8 oxidation state	(c) Os
(ii) 3d block element that can show upto +7 oxidation state	(a) Mn
(iii) 3d block element with highest melting point	(b) Cr

Q55Written answer

Match the statements given in Column I with the oxidation states given in Column II.

Column I	Column II
(i) Oxidation state of Mn in \[Mn{O_2}\] is	(a) + 2
(ii) Most stable oxidation state of Mn is	(b) + 3
(iii) Most stable oxidation state of Mn in oxides is	(c) + 4
(iv) Characteristic oxidation state of lanthanoids is	(d) + 5
	(e) + 7

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Column I	Column II
(i) Oxidation state of Mn in \[{\text{Mn}}{{\text{O}}_2}\]is	(c) + 4
(ii) Most stable oxidation state of Mn is	(a) + 2
(iii) Most stable oxidation state of Mn in oxides is	(e) + 7
(iv) Characteristic oxidation state of lanthanoids is	(b) + 3

Q56Written answer

Match the solutions given in Column I and the colours given in Column II.

Column I (Aqueous solution of salt)	Column II (Colour)
(i)\[ FeS{O_4} .7{H_2}O\]	(a) Green
(ii)\[NiC{l_2} .4{H_2}O\]	(b) Light pink
(iii)\[MnC{l_2} .4{H_2}O\]	(c) Blue
(iv)\[CoC{l_2} .6{H_2}O\]	(d) Pale green
(v) \[C{u_2}C{l_2}\]	(e) Pink
	(f) Colourless

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Column I (Aqueous solution of salt)	Column II (Colour)
(i)\[{\text{ FeS}}{{\text{O}}_{\text{4}}}{\text{ }}{\text{.7}}{{\text{H}}_{\text{2}}}{\text{O}}\]	(d) Pale green
(ii)\[{\text{NiC}}{{\text{l}}_{\text{2}}}{\text{ }}{\text{.4}}{{\text{H}}_{\text{2}}}{\text{O}}\]	(a) Green
(iii)\[{\text{MnC}}{{\text{l}}_{\text{2}}}{\text{ }}{\text{.4}}{{\text{H}}_{\text{2}}}{\text{O}}\]	(b) Light pink
(iv)\[{\text{CoC}}{{\text{l}}_{\text{2}}}{\text{ }}{\text{.6}}{{\text{H}}_{\text{2}}}{\text{O}}\]	(e) Pink
(v) \[{\text{C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}{\text{}}\]	(f) Colourless

Q57Written answer

Match the property given in Column I with the element given in Column II.

Column I (Property)	Column II (Elements)
(i) Lanthanoid which shows +4 oxidation state	(a) Pm
(ii) Lanthanoid which can show +2 oxidation state	(b) Ce
(iii) Radioactive lanthanoid	(c) Lu
(iv) Lanthanoid which has \[4{f^7}\]electronic configuration in +3 oxidation state	(d) Eu
(v) Lanthanoid which has \[4{f^{14}}\]electronic configuration in +3 oxidation state	(e) Gd
	(f) Dy

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Column I (Property)	Column II (Elements)
(i) Lanthanoid which shows +4 oxidation state	(b) Ce
(ii) Lanthanoid which can show +2 oxidation state	(d) Eu
(iii) Radioactive lanthanoid	(a) Pm
(iv) Lanthanoid which has \[4{f^7}\]electronic configuration in +3 oxidation state	(e) Gd
(v) Lanthanoid which has \[4{f^{14}}\]electronic configuration in +3 oxidation state	(c) Lu

Q58Written answer

Match the properties given in Column I with the medals given in Column II.

Column I (Property)	Column II (Metal)
(i) Element with highest second ionisation enthalpy	(a) Co
(ii) Element with highest third ionisation Enthalpy	(b) Cr
(iii) M in \[M {\left( {CO} \right)_6}\] is	(c) Cu
(iv) Element with highest heat of atomisation	(d) Zn
	(e) Ni

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Column I (Property)	Column II (Metal)
(i) Element with highest second ionisation enthalpy	(c) Cu
(ii) Element with highest third ionisation Enthalpy	(d) Zn
(iii) M in \[{\text{M }}{\left( {{\text{CO}}} \right)_6}\]is	(b) Cr
(iv) Element with highest heat of atomisation	(e) Ni

ASSERTION AND REASON TYPE:

Q59Written answer

Assertion (A): \[C{u^{2 + }}\] iodide is not known.

Reason (R): \[C{u^{2 + }}\] oxidises I to iodine.

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Ans: All halogens combine with copper to form copper halides except iodine. The reason behind this is that \[{\text{C}}{{\text{u}}^{{\text{2 + }}}}\] oxidises iodide (-1) to iodine (0). Therefore, \[{\text{C}}{{\text{u}}^{{\text{2 + }}}}\]iodide does not exist .Both the statements assertion and reason are correct and reason is the correct explanation of assertion.

Q60Written answer

Assertion (A): Separation of \[Zr\] and \[Hf\] is difficult.

Reason (R): Because \[Zr\] and \[Hf\] lie in the same group of the periodic table.

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Ans: Although \[{\text{Zr}}\] and \[{\text{Hf}}\] lie in same group but As an effect of lanthanide contraction, zirconium and hafnium have similar radius of 160pm and 159 pm respectively. Due to this similarity in their size, they show similar physical and chemical properties. As a result, \[{\text{Zr}}\] and \[{\text{Hf}}\] are difficult to separate. Both the statements assertion and reason are correct but reason is not the correct explanation of assertion.

Q61Written answer

Assertion (A): Actinoids form relatively less stable complexes as compared to lanthanoids.

Reason (R): Actinoids can utilize their 5d orbitals along with 6d orbitals in bonding but lanthanoids do not use their 4f orbital for bonding.

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Ans: Actinoids are more reactive than lanthanoids as they involve their 5d-orbital in the bond formation process while due to effectively shielded and greater nuclear charge 4f-orbitals are not available for bonding. Thus, lanthanoids comparatively form less complexes than actinoids.

Assertion is not true but reason is true.

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