Why is \[HCl\] not used to make the medium acidic in oxidation reactions of \[KMn{O_4}\]in acidic medium?
(A) Both\[HCl\] and \[KMn{O_4}\] act as oxidizing agents.
(B) \[KMn{O_4}\] oxidises \[HCl\] into \[C{l_2}\]which is also an oxidizing agent.
(C) \[KMn{O_4}\] is a weaker oxidizing agent than \[HCl\].
(D) \[KMn{O_4}\] acts as a reducing agent in the presence of \[HC{\text{l}}\].
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Ans: (B) \[KMn{O_4}\] oxidises \[HCl\] into \[C{l_2}\]which is also an oxidizing agent.
\[{\text{HCl}}\] is not used in titrations involving\[{\text{KMn}}{{\text{O}}_{\text{4}}}\] as it produces unsatisfactory results. When\[{\text{HCl}}\] is added to \[{\text{KMn}}{{\text{O}}_{\text{4}}}\], it itself acts as reducing agent and coverts \[{\text{HCl}}\] to \[{\text{C}}{{\text{l}}_{\text{2}}}\].