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NCERT Exemplar · Class 12 · Chemistry

Chapter 6: General Principles and Processes of Isolation of Elements

Practice each question, then open the answer or worked solution.

II. Multiple Choice Questions (Type-II)

31 questions
Q24Written answer

In which of the following method of purification, metal is converted to its volatile

compound which is decomposed to give pure metal?

(i) heating with a stream of carbon monoxide.

(ii) heating with iodine.

(iii) liquation.

(iv) distillation.

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Worked solution

Option (i) and (ii) are the answers.

Q25Written answer

Which of the following statements are correct?

(i) A depressant prevents a certain type of particle to come to the froth.

(ii) Copper matte contains Cu2S and ZnS.

(iii) The solidified copper obtained from the reverberatory furnace has blistered

appearance due to evolution of SO2

during the extraction.

(iv) Zinc can be extracted by self-reduction.

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Worked solution

Option (i) and (iii) are the answers.

Q26Written answer

In the extraction of chlorine from brine _____________.

A. ΔG° for the overall reaction is negative.

B. ΔG° for the overall reaction is positive.

C. E° for the overall reaction has a negative value.

D. E° for the overall reaction has a positive value.

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Worked solution

Option (ii) and (iii) are the answers.

III. Short Answer Type

Q27Written answer

Why is an external emf of more than 2.2V required for the extraction of Cl2 from brine?

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Worked solution

2Cl– (aq) + 2H2O(l) → 2OH– (aq) + H2(g) + Cl2(g)

The ΔGᶱ for this reaction is +422kJmol-1.

Using the formula, ΔGᶱ = -nFE°

E° = 422 x 103/2×96500

we get = -2.2V

For the reaction to take place the external voltage should be greater than 2.2V otherwise the reaction will not happen.

Q28Written answer

At temperatures above 1073K coke can be used to reduce FeO to Fe. How can you justify this reduction with the Ellingham diagram?

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Worked solution

The ∆G for the formation of FeO is less negative than ∆G for the formation of carbon monoxide from carbon. The summation of both the ∆G will be negative about 1073K. Above 1073K the line for the formation of FeO lies above the line for the oxidation of C to CO.

So, in this range, coke will be reducing the FeO and will itself be oxidised to CO.

FeO + C → Fe + CO

Q29Written answer

Wrought iron is the purest form of iron. Write a reaction used for the preparation of wrought iron from cast iron. How can the impurities of sulphur, silicon and phosphorus be removed from cast iron?

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Worked solution

Fe2O3 + 3 C → 2 Fe + 3CO

Limestone is added as a flux to remove the impurities of sulphur, silicon and phosphorous. They form a slag which can be easily removed. The metal is removed from the slag by passing through rollers.

Q30Written answer

How is copper extracted from low-grade copper ores?

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Worked solution

Copper is extracted by hydrometallurgy from low-grade copper ores. Cu is treated with scrap iron or H2. It is leached out with acid.

Cu2+(aq) + H2(g) → Cu(s) + 2H+(aq)

Q31Written answer

Write two basic requirements for refining of metal by Mond process and by Van Arkel Method.

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Worked solution

(i) The metal should react easily with the reagent to form the complex.

(ii) The volatile complex should easily decompose and not give any side products and the recovery should also be easy.

Q32Written answer

Although carbon and hydrogen are better-reducing agents they are not used to reduce metallic oxides at high temperatures. Why?

Carbon and hydrogen will not reduce oxides to metals but they will instead form hydrides and carbides. Therefore, they are not used as reducing agents.

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Worked solution

Solution coming soon.

Q33Written answer

How do we separate two sulphide ores by Froth Floatation Method? Explain with an example.

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Worked solution

Two sulphide ores competing to come to the froth can be separated by adjusting the oil to water proportion or by adding a depressant like NaCN. If we have two sulphide ores, ZnS and PbS, NaCN will prevent ZnS from coming to the froth and instead PbS will form the froth. This way the two ores can be separated.