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NCERT · Class 6 · Maths

Chapter 10: Mensuration

Practice each question, then open the answer or worked solution.

Exercise 10.3

Textbook page 219 · 12 questions
Q1Written answer

Find the area of the rectangles whose sides are:

(a) 3 cm and 4 cm

(b) 12 m and 21 m

(c) 2 km and 3 km

(d) 2 m and 70 cm

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Worked solution

We know that

Area of rectangle = Length × Breadth

(a) l = 3 cm and b = 4 cm

Area = l × b = 3 × 4

= 12 cm2

(b) l = 12 m and b = 21 m

Area = l × b = 12 × 21

= 252 m2

(c) l = 2 km and b = 3 km

Area = l × b = 2 × 3

= 6 km2

(d) l = 2 m and b = 70 cm = 0.70 m

Area = l × b = 2 × 0.70

= 1.40 m2

Q2Written answer

Find the areas of the squares whose sides are:

(a) 10 cm

(b) 14 cm

(c) 5 m

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Worked solution

(a) Area of square = side2

= 102

= 100 cm2

(b) Area of square = side2

= 142

= 196 cm2

(c) Area of square = side2

= 52

=25 cm2

Q3Written answer

The length and breadth of the three rectangles are as given below:

(a) 9 m and 6 m

(b) 17 m and 3 m

(c) 4 m and 14 m

Which one has the largest area, and which one has the smallest?

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Worked solution

(a) Area of rectangle = l × b

= 9 × 6

= 54 m2

(b) Area of rectangle = l × b

= 17 × 3

= 51 m2

(c) Area of rectangle = l × b

= 4 × 14

= 56 m2

The area of rectangle 56 m2, i.e. (c), is the largest area and the area of rectangle 51 m2, i.e. (b), is the smallest area

Q4Written answer

The area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.

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Worked solution

Area of rectangle = length × width

300 = 50 × width

width = 300 / 50

width = 6 m

∴ The width of the garden is 6 m.

Q5Written answer

What is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of ₹ 8 per hundred sq m?

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Worked solution

Area of land = length × breadth

= 500 × 200

= 1,00,000 m2

∴ Cost of tiling 1,00,000 sq m of land = (8 × 1,00,000) / 100

= ₹ 8000

∴ The cost of tiling a rectangular plot of land is ₹ 8000.

Q6Written answer

A tabletop measures 2 m by 1 m 50 cm. What is its area in square metres?

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Worked solution

Given

l = 2m

b = 1m 50 cm = 1.50 m

Area = l × b = 2 × 1.50

= 3 m2

∴ The area of the tabletop is 3 m2.

Q7Written answer

A room is 4 m long and 3 m 50 cm wide. How many square metres of carpet are needed to cover the floor of the room?

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Worked solution

Given

l = 4m

b = 3 m 50 cm = 3.50 m

Area = l × b = 4 × 3.50

= 14 m2

∴ The carpet required to cover the floor is 14 m2.

Q8Written answer

A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.

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Worked solution

Area of floor = l × b = 5 × 4

= 20 m2

Area of square carpet = 3 × 3

= 9 m2

Area of floor that is not carpeted = 20 – 9

= 11 m2

∴ The area of the floor that is not carpeted is 11 m2.

Q9Written answer

Five square flower beds, each of sides 1 m, are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

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Worked solution

Area of flower square bed = 1 × 1

= 1 m2

Area of 5 square bed = 1 × 5

= 5 m2

Area of land = 5 × 4

= 20 m2

Remaining part of the land = Area of land – Area of 5 square bed

= 20 – 5

= 15 m2

∴ The remaining part of the land is 15 m2.

Q10Written answer

By splitting the following figures into rectangles, find their areas (The measures are given in centimetres).

NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.3 - 1

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Worked solution

(a)

NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.3 - 2

Area of yellow region = 3 × 3

= 9 cm2

Area of orange region = 1× 2

= 2 cm2

Area of grey region = 3 × 3

= 9 cm2

Area of brown region = 2 × 4

= 8 cm2

Total area = 9 + 2 + 9 + 8

= 28 cm2

∴ The total area is 28 cm2.

(b)

NCERT Solutions for Class 6 Maths Chapter 10 Exercise 10.3 - 3

Area of brown region = 3 × 1

= 3 cm2

Area of orange region = 3 × 1

= 3 cm2

Area of grey region = 3 × 1

= 3 cm2

Total area = 3 + 3 + 3

= 9 cm2

∴ The total area is 9 cm2.