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NCERT · Class 11 · Maths

Chapter 8: Binomial Theorem Exercise 8.2

Practice each question, then open the answer or worked solution.

Questions

12 questions
Q11Written answer

Prove that the coefficient of xn in the expansion of (1 + x)2n is twice the coefficient of xn in the expansion of (1 + x)2n – 1.

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Worked solution

The general term Tr+1 in the binomial expansion is given by Tr+1 = nCr an-r br

The general term for binomial (1+x)2n is

Tr+1 = 2nCr xr …………………..1

To find the coefficient of xn

r = n

Tn+1 = 2nCn xn

The coefficient of xn = 2nCn

The general term for binomial (1+x)2n-1 is

Tr+1 = 2n-1Cr xr

To find the coefficient of xn

Putting n = r

Tr+1 = 2n-1Cr xn

The coefficient of xn = 2n-1Cn

We have to prove

Coefficient of xn in (1+x)2n = 2 coefficient of xn in (1+x)2n-1

Consider LHS = 2nCn

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem Image 29

Q12Written answer

Find a positive value of m for which the coefficient of x2 in the expansion (1 + x)m is 6.

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Worked solution

The general term Tr+1 in the binomial expansion is given by Tr+1 = nCr an-r br

Here, a = 1, b = x and n = m

Putting the value,

Tr+1 = m Cr 1m-r xr

= m Cr xr

We need the coefficient of x2

∴ putting r = 2

T2+1 = mC2 x2

The coefficient of x2 = mC2

Given that coefficient of x2 = mC2 = 6

NCERT Solutions for Class 11 Maths Chapter 8 Binomial Theorem Image 30

⇒ m (m – 1) = 12

⇒ m2– m – 12 =0

⇒ m2– 4m + 3m – 12 =0

⇒ m (m – 4) + 3 (m – 4) = 0

⇒ (m+3) (m – 4) = 0

⇒ m = – 3, 4

We need the positive value of m, so m = 4

Access Other Exercise Solutions of Class 11 Maths Chapter 8 – Binomial Theorem

Exercise 8.1 Solutions 14 Questions

Miscellaneous Exercise on Chapter 8 Solutions 10 Questions

Also explore – NCERT Class 11 Maths Solutions