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Previous year question hub

Electromagnetism - Physics Previous Year Questions

Practice Electromagnetism - Physics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.

1Papers
1Years
11Questions
1Topics

Electromagnetism question pattern

Every graph below is calculated only from this selection.

Questions by year

Year-wise coverage for Electromagnetism. Each bar uses a separate theme-derived color.

Difficulty distribution

How the classified questions are distributed by difficulty.

Not classified 11 100%

Question type distribution

MCQ, numerical, multiple-select and other formats found in these papers.

Multiple Choices 11 100%

Subject weightage

Top subjects by unique question coverage.

Physics
11 Qs

Most asked topics

Top topics across the included previous year papers.

Electromagnetism
11 Qs

Subtopic coverage

Top subtopics inside this exact selection.

Capacitor
3 Qs
Electromagnetic Waves
2 Qs
Electrostatics
1 Qs
Electromagnetic Induction
1 Qs
Magnetism And Matter
1 Qs
Alternating Current
1 Qs
Moving Charges And Magnetism
1 Qs
Current Electricity
1 Qs

Paper coverage

Question coverage for the most populated papers. Every active PYP paper remains listed below.

VITEEE 2025
11 Qs

Browse by subtopics

Open a focused page built from the same verified paper data.

Included previous year papers

Newest papers appear first. Sort by year, question coverage or name.

PaperYear / sessionQuestions in this viewOpen
VITEEE 2025202511View paper

Sample previous year questions

A varied preview from the papers represented in this selection, with every available option.

1
2025 · Physics · Electromagnetism · Capacitor
VITEEE 2025

Capacity of a parallel plate capacitor in the absence of dielectric medium is $C_0$. A sheet of dielectric constant $k$ and thickness of one-fourth of the plate separation is inserted between the plates. If the new capacity is $C$, then $\frac{C}{C_0}$ is

A

$\frac{3 k+1}{2 k}$

B

$\frac{3 k+1}{4 k}$

C

$\frac{2 k}{3 k+1}$

D

$\frac{4 k}{3 k+1}$

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2
2025 · Physics · Electromagnetism · Electrostatics
VITEEE 2025

In given situation, force on charge $Q_3$ is

VITEEE 2025 Physics - Electrostatics Question 1 English
A

140 N

B

330 N

C

120 N

D

290 N

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3
2025 · Physics · Electromagnetism · Electromagnetic Induction
VITEEE 2025

A conductor of length 0.6 m is moving with a speed of $5 \mathrm{~m} / \mathrm{s}$ perpendicular to a magnetic field of intensity $0.8 \mathrm{~Wb} / \mathrm{m}^2$. The induced emf across the conductor is

A

2.4 V

B

2.52 V

C

25.2 V

D

5.04 V

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4
2025 · Physics · Electromagnetism · Magnetism And Matter
VITEEE 2025

A cylindrical magnet has a length of 15 cm and diameter 3 cm . If it has uniform magnetisation of $4.0 \times 10^3 \mathrm{Am}^{-1}$, then magnetic dipole moment is

A

$0.42 \mathrm{JT}^{-1}$

B

$0.84 \mathrm{JT}^{-1}$

C

$0.21 \mathrm{JT}^{-1}$

D

$0.58 \mathrm{JT}^{-1}$

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5
2025 · Physics · Electromagnetism · Alternating Current
VITEEE 2025

Which of the following statement is correct regarding the AC circuit shown in the adjacent figure?

VITEEE 2025 Physics - Alternating Current Question 1 English
A

The rms value of current through the circuit is $i_{\text {rms }}=5 \sqrt{2} \mathrm{~A}$

B

The phase difference between source emf and current is $\phi=\cos ^{-1}\left(\frac{1}{3}\right)$

C

Average power dissipated in the circuit is 500 W

D

None of the above

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6
2025 · Physics · Electromagnetism · Electromagnetic Waves
VITEEE 2025

If the magnetic field in plane electromagnetic wave is

$$\mathbf{B}=3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{j}} \mathrm{T},$$

then find the expression of electric field?

A

$60 \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{k}} \mathrm{V} / \mathrm{m}$

B

$3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathrm{i}} \mathrm{V} / \mathrm{m}$

C

$9 \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{k}} \mathrm{V} / \mathrm{m}$

D

$3 \times 10^{-8} \sin \left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{\mathbf{j}} \mathrm{V} / \mathrm{m}$

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