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Previous year question hub

Chemical Equilibrium - Physical Chemistry - Chemistry Previous Year Questions

Practice Chemical Equilibrium - Physical Chemistry - Chemistry previous year questions organised from real papers, with year-wise coverage and clear topic navigation.

5Papers
5Years
5Questions
1Topics

Chemical Equilibrium question pattern

Every graph below is calculated only from this selection.

Questions by year

Year-wise coverage for Chemical Equilibrium. Each bar uses a separate theme-derived color.

Difficulty distribution

How the classified questions are distributed by difficulty.

Not classified 5 100%

Question type distribution

MCQ, numerical, multiple-select and other formats found in these papers.

Multiple Choices 5 100%

Subject weightage

Top subjects by unique question coverage.

Chemistry
5 Qs

Most asked topics

Top topics across the included previous year papers.

Physical Chemistry
5 Qs

Subtopic coverage

Top subtopics inside this exact selection.

Chemical Equilibrium
5 Qs

Paper coverage

Question coverage for the most populated papers. Every active PYP paper remains listed below.

WB JEE 2025
1 Qs
WB JEE 2024
1 Qs
WB JEE 2020
1 Qs
WB JEE 2019
1 Qs
WB JEE 2017
1 Qs

Included previous year papers

Newest papers appear first. Sort by year, question coverage or name.

PaperYear / sessionQuestions in this viewOpen
WB JEE 202520251View paper
WB JEE 202420241View paper
WB JEE 202020201View paper
WB JEE 201920191View paper
WB JEE 201720171View paper

All Chemical Equilibrium previous year questions

Practice every matching question in batches of 20, with every available option.

1
2017 · Chemistry · Physical Chemistry · Chemical Equilibrium
WB JEE 2017
Equilibrium constants for the following reactions at 1200 K are given

2H2O(g) \(\rightleftharpoons\) 2H2(g) + O2(g), K1 = 6.4 \(\times\) 10\(-\)8

2CO2(g) \(\rightleftharpoons\) 2CO(g) + O2(g), K2 = 1.6 \(\times\) 10\(-\)6

The equilibrium constant for the reaction?

H2(g) + CO2(g) \(\rightleftharpoons\) CO(g) + H2O(g) at 1200 K will be
A
0.05
B
20
C
0.2
D
5.0
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2
2019 · Chemistry · Physical Chemistry · Chemical Equilibrium
WB JEE 2019
In the equilibrium, H2 + I2 \(\rightleftharpoons\) 2HI, if at a given temperature the concentration of the reactants are increased, the value of the equilibrium constant, KC, will
A
increase
B
decrease
C
remain the same
D
cannot be predicted with certainty
Open complete paper
3
2020 · Chemistry · Physical Chemistry · Chemical Equilibrium
WB JEE 2020
The equilibrium constant for the following reactions are given at 25\(^\circ\)C

\(2A\) \(\rightleftharpoons\) B + C, K1 = 1.0

\(2B\) \(\rightleftharpoons\) C + D, K2 = 16

\(2C + 2D\) \(\rightleftharpoons\) 2P, K3 = 25

The equilibrium constant for the reaction

P \(\rightleftharpoons\) \(A + {1 \over 2}\)B at 25\(^\circ\)C is
A
\({1 \over 20}\)
B
20
C
\({1 \over 42}\)
D
21
Open complete paper
4
2024 · Chemistry · Physical Chemistry · Chemical Equilibrium
WB JEE 2024

Which of the following statements is true about equilibrium constant and rate constant of a single step chemical reaction?

A
Equilibrium constant may increase or decrease but rate constant always increases with temperature.
B
Both equilibrium constant and rate constant increase with temperature.
C
Rate constant may increase or decrease but equilibrium constant always increases with temperature.
D
Both equilibrium constant and rate constant decrease with temperature.
Open complete paper
5
2025 · Chemistry · Physical Chemistry · Chemical Equilibrium
WB JEE 2025

Consider the following gas phase dissociation, $\mathrm{PCl}_5(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_3(\mathrm{~g})+\mathrm{Cl}_2(\mathrm{~g})$ with equilibrium constant $K_P$ at a particular temperature and at pressure $P$. The degree of dissociation ( $\alpha$ ) for $\mathrm{PCl}_5(\mathrm{~g})$ is

A
$\alpha=\left(\frac{\mathrm{K}_{\mathrm{P}}}{\mathrm{K}_{\mathrm{P}}+\mathrm{P}}\right)^{1 / 3}$
B
$\boldsymbol{\alpha}=\left(\frac{\mathrm{K}_{\mathrm{P}}}{\mathrm{K}_{\mathrm{P}}+\mathrm{P}}\right)$
C
$\alpha=\left(\frac{\mathrm{K}_{\mathrm{P}}}{\mathrm{K}_{\mathrm{P}}+\mathrm{P}}\right)^{1 / 2}$
D
$\alpha=\left(\frac{\mathrm{K}_{\mathrm{P}}}{\mathrm{K}_{\mathrm{P}}+\mathrm{P}}\right)^2$
Open complete paper