Capacitor - Electromagnetism - Physics Previous Year Questions

Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

A parallel plate capacitor of capacitance \(5 \mu \mathrm{F}\) is charged to \(120 \mathrm{~V}\) and then connected to another uncharged capacitor. If the potential falls to \(40 \mathrm{~V}\), and capacitance of the second capacitor is

A capacitor is filled with two dielectrics of the same dimensions but of dielectric constants 2 and 3 as shown in Fig.(a) and then in Fig.(b). Then ratio of the capacitor in the two arrangements is

A parallel plate capacitor with plate area \(A\) and separation between the plates \(d\) is charged by a constant current \(i\). Consider a plane surface of area \(A / 2\) parallel to the plates and drawn simultaneously between the plates. The displacement current through this area is

A parallel plate capacitor with air between the plates has a capacitance of \(15 \mathrm{~pF}\). the separation between the plates is \(d\). The space between the plates is now filled with two dielectrics constant \(k_1=3\) and thickness \(d / 3\) while the other one has dielectric constant \(k_2=6\) and thickness \(2 d / 3\). Capacitance of the capacitor is now