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Previous year question hub

Differential Equations - Calculus - Mathematics Previous Year Questions

Practice Differential Equations - Calculus - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.

4Papers
4Years
13Questions
1Topics

Differential Equations question pattern

Every graph below is calculated only from this selection.

Questions by year

Year-wise coverage for Differential Equations. Each bar uses a separate theme-derived color.

Difficulty distribution

How the classified questions are distributed by difficulty.

Not classified 13 100%

Question type distribution

MCQ, numerical, multiple-select and other formats found in these papers.

Multiple Choices 13 100%

Subject weightage

Top subjects by unique question coverage.

Mathematics
13 Qs

Most asked topics

Top topics across the included previous year papers.

Calculus
13 Qs

Subtopic coverage

Top subtopics inside this exact selection.

Differential Equations
13 Qs

Paper coverage

Question coverage for the most populated papers. Every active PYP paper remains listed below.

VITEEE 2024
1 Qs
VITEEE 2023
4 Qs
VITEEE 2022
5 Qs
VITEEE 2021
3 Qs

Included previous year papers

Newest papers appear first. Sort by year, question coverage or name.

PaperYear / sessionQuestions in this viewOpen
VITEEE 202420241View paper
VITEEE 202320234View paper
VITEEE 202220225View paper
VITEEE 202120213View paper

All Differential Equations previous year questions

Practice every matching question in batches of 20, with every available option.

1
2021 · Mathematics · Calculus · Differential Equations
VITEEE 2021

The general solution of the linear differential equation \(\frac{d y}{d x}+\sec x \cdot y=\tan x\left(0 \leq x \leq \frac{\pi}{2}\right)\) is

A
\(y=-x(\sec x+\tan x)^{-1}+\frac{c}{\sec x+\tan x}+1\)
B
\(y=x+\frac{C}{\sec x+\tan x}+\frac{1}{\tan x}\)
C
\(y=\frac{x+1}{\sec x+\tan x}+C\)
D
\(y=x+\sec x+\tan x+C\)
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2
2021 · Mathematics · Calculus · Differential Equations
VITEEE 2021

The particular solution of the differential equation \(\frac{d y}{d x}+y \cot x=2 x+x^2 \cot x\), such that \(y(\pi / 2)=0\) is

A
\(y=\frac{\pi^2}{4 \cos x},(x \neq 0)\)
B
\(y=x^2-\frac{\pi}{2} \tan x\)
C
\(y=\frac{2 x}{\sin x}+\frac{1}{x^2},(x \neq 0)\)
D
\(y=x^2-\frac{\pi^2}{4 \sin x}(\sin x \neq 0)\)
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3
2021 · Mathematics · Calculus · Differential Equations
VITEEE 2021

On solving the differential equation \(x^2 y d x-\left(x^3+y^3\right) d y=0\), the value of \(\log y\) is

A
\(\frac{x^3}{3 y^3}+C\)
B
\(\frac{x^2}{y^2}+C\)
C
\(\frac{x^2}{3 y^3}+C\)
D
\(\frac{x^3}{x^3+y^3}+C\)
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4
2022 · Mathematics · Calculus · Differential Equations
VITEEE 2022

Find the solution of equation \(\frac{d y}{d x}=\frac{1}{\cos (x+y)}\)

A
\(\cot \left(\frac{x+y}{2}\right)+c\)
B
\(\sec \left(\frac{x+y}{2}\right)+c\)
C
\(\tan \left(\frac{x+y}{2}\right)+c\)
D
\(-\cot \left(\frac{x-y}{2}\right)+c\)
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5
2022 · Mathematics · Calculus · Differential Equations
VITEEE 2022

Find the solution of \(\frac{d y}{d x}=\frac{1}{\cos (x-y)}\)

A
\(-\cot \left(\frac{x+y}{2}\right)+c\)
B
\(\operatorname{cosec}^2\left(\frac{x+y}{2}\right)+c\)
C
\(\tan \left(\frac{x+y}{2}\right)+c\)
D
\(\cot \left(\frac{x-y}{2}\right)+c\)
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6
2022 · Mathematics · Calculus · Differential Equations
VITEEE 2022

The solution of the equation \(\frac{d y}{d x}+x(x+y)=x^3(x+y)^3-1\) is

A
\(\frac{1}{(x+y)^2}=x^2+1+c e^x\)
B
\(\frac{1}{(x+y)^2}=x^2+1+c e^x\)
C
\(\frac{1}{(x+y)^2}=x^2+1+c e^{x^2}\)
D
\(\frac{1}{x+y}=x+1+c e^{x^2}\)
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7
2022 · Mathematics · Calculus · Differential Equations
VITEEE 2022

The solution of \(\frac{d y}{d x}=1+x+y+x y\) is

A
\(\log (1+y)=x+\frac{x^2}{2}+C\)
B
\(x+y=C(1+x y)\)
C
\(\log (1+x)+x+y=C\)
D
None of the above
Open complete paper
8
2022 · Mathematics · Calculus · Differential Equations
VITEEE 2022

If \(p\) and \(q\) are order and degree of the question \(\left(\frac{d^2 y}{d x^2}\right)^4+4 \frac{\left(\frac{d^2 y}{d x^2}\right)^2}{\left(\frac{d^3 y}{d x^3}\right)^3}+\frac{d^3 y}{d x^3}=x^2-1\), then

A
\(p=3, q=3\)
B
\(p=3, r=2\)
C
\(p=4, r=3\)
D
\(p=3, r=4\)
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9
2023 · Mathematics · Calculus · Differential Equations
VITEEE 2023

The solution of \(d y / d x=1+x+y+x y\) is

A
\(x+y=c(1+x y)\)
B
\(\log (1+x)+x+y=c\)
C
\(\log (1+y)=x+\frac{x^2}{2}+C\)
D
None of these
Open complete paper
10
2023 · Mathematics · Calculus · Differential Equations
VITEEE 2023

The solution of differential equation \(y y^{\prime}=x\left(\frac{y^2}{x^2}+\frac{f\left(y^2 / x^2\right)}{f^{\prime}\left(y^2 / x^2\right)}\right)\) is

A
\(x^2 f\left(\frac{y^2}{x^2}\right)=c\)
B
\(x^2 f\left(\frac{y^2}{x^2}\right)=c^2 y^2\)
C
\(f\left(\frac{y^2}{x^2}\right)=c x^2\)
D
\(f\left(\frac{y^2}{x^2}\right)=\frac{c y}{x}\)
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11
2023 · Mathematics · Calculus · Differential Equations
VITEEE 2023

If \(m\) and \(n\) are order and degree of the question \(\left(\frac{d^2 y}{d x^2}\right)^4+8 \frac{\left(d^2 y / d x^2\right)^3}{\left(d^4 y / d x^4\right)^5}+\left(\frac{d^4 y}{d x^4}\right)=x^2+4\), then \(m-n\) is equal to

A
2
B
6
C
\(-\)4
D
\(-\)2
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12
2023 · Mathematics · Calculus · Differential Equations
VITEEE 2023

If \(x d y / d x=x^2+y-2, y(1)=1\), then \(y(2)\) is equal to

A
2
B
4
C
1
D
8
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13
2024 · Mathematics · Calculus · Differential Equations
VITEEE 2024

The differential equation corresponding to the family of curves $y=e^x(a x+b)$ is

A
$\frac{d^2 y}{d x^2}+Z \frac{d y}{d x}-y=0$
B
$\frac{d^2 y}{d x^2}-2 \frac{d y}{d x}+y=0$
C
$\frac{d^2 y}{d x^2}+2 \frac{d y}{d x}+y=0$
D
$\frac{d^2 y}{d x^2}-2 \frac{d y}{d x}-y=0$
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