Difficulty distribution
How the classified questions are distributed by difficulty.
Your cart is empty.
Practice Differential Equations - Calculus - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
Every graph below is calculated only from this selection.
Year-wise coverage for Differential Equations. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| VITEEE 2024 | 2024 | 1 | View paper |
| VITEEE 2023 | 2023 | 4 | View paper |
| VITEEE 2022 | 2022 | 5 | View paper |
| VITEEE 2021 | 2021 | 3 | View paper |
Practice every matching question in batches of 20, with every available option.
The general solution of the linear differential equation \(\frac{d y}{d x}+\sec x \cdot y=\tan x\left(0 \leq x \leq \frac{\pi}{2}\right)\) is
The particular solution of the differential equation \(\frac{d y}{d x}+y \cot x=2 x+x^2 \cot x\), such that \(y(\pi / 2)=0\) is
On solving the differential equation \(x^2 y d x-\left(x^3+y^3\right) d y=0\), the value of \(\log y\) is
Find the solution of equation \(\frac{d y}{d x}=\frac{1}{\cos (x+y)}\)
Find the solution of \(\frac{d y}{d x}=\frac{1}{\cos (x-y)}\)
The solution of the equation \(\frac{d y}{d x}+x(x+y)=x^3(x+y)^3-1\) is
The solution of \(\frac{d y}{d x}=1+x+y+x y\) is
If \(p\) and \(q\) are order and degree of the question \(\left(\frac{d^2 y}{d x^2}\right)^4+4 \frac{\left(\frac{d^2 y}{d x^2}\right)^2}{\left(\frac{d^3 y}{d x^3}\right)^3}+\frac{d^3 y}{d x^3}=x^2-1\), then
The solution of \(d y / d x=1+x+y+x y\) is
The solution of differential equation \(y y^{\prime}=x\left(\frac{y^2}{x^2}+\frac{f\left(y^2 / x^2\right)}{f^{\prime}\left(y^2 / x^2\right)}\right)\) is
If \(m\) and \(n\) are order and degree of the question \(\left(\frac{d^2 y}{d x^2}\right)^4+8 \frac{\left(d^2 y / d x^2\right)^3}{\left(d^4 y / d x^4\right)^5}+\left(\frac{d^4 y}{d x^4}\right)=x^2+4\), then \(m-n\) is equal to
If \(x d y / d x=x^2+y-2, y(1)=1\), then \(y(2)\) is equal to
The differential equation corresponding to the family of curves $y=e^x(a x+b)$ is