Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Matrices And Determinants - Algebra - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Matrices And Determinants. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
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Top topics across the included previous year papers.
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Question coverage for the most populated papers. Every active PYP paper remains listed below.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| VITEEE 2024 | 2024 | 2 | View paper |
| VITEEE 2023 | 2023 | 3 | View paper |
| VITEEE 2022 | 2022 | 1 | View paper |
| VITEEE 2021 | 2021 | 2 | View paper |
Practice every matching question in batches of 20, with every available option.
If \(A^{-1}=\left[\begin{array}{rr}5 & -2 \\ -7 & 3\end{array}\right]\) and \(B^{-1}=\frac{1}{2}\left[\begin{array}{rr}9 & -7 \\ -8 & 6\end{array}\right]\), then \((A B)^{-1}\) is equal to
If \(A=\left[\begin{array}{ll}3 & -4 \\ 1 & -1\end{array}\right]\), then \(\left(A-A^{\prime}\right)\) is equal to (where, \(A^{\prime}\) is transpose of matrix \(A\) )
For all values of \(\lambda\), rank of matrix
$$A=\left[\begin{array}{ccc} { }^h C_0 & { }^4 C_3 & { }^5 C_4 \\ \[\lambda & 8 & 8 \lambda-6 \\\] 1+\lambda^2 & 8 \lambda+4 & 2 \lambda+21 \end{array}\right]$$
If matrix \(A=\left[\begin{array}{ccc}0 & 2 b & -2 \\ 3 & 1 & 3 \\ 3 a & 3 & -1\end{array}\right]\) is given to be symmetric, then the value of \(a b\) is
Suppose, \(A=\left[\begin{array}{lll}a_1 & b_1 & c_1 \\ a_2 & b_2 & c_2 \\ a_3 & b_3 & c_3\end{array}\right]\) is an adjoint of the matrix \(\left[\begin{array}{rrr}1 & 3 & 3 \\ 1 & 4 & 3 \\ 1 & 3 & 4\end{array}\right]\). The value of \(\frac{a_1+b_2+c_3}{b_1 a_2}\) is
The determinant of the matrix \(\left[\begin{array}{ccc}1 & 4 & 8 \\ 1 & 9 & 27 \\ 1 & 16 & 64\end{array}\right]\) is
If $A, B$ are two square matrices, such that $A B=A, B A=B$, then $(A+B)^7$ equals
If $A=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]$ and $B=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right]$, then $\left(B B^T A\right)^5$ is equal to