Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Complex Numbers - Algebra - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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Year-wise coverage for Complex Numbers. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| VITEEE 2024 | 2024 | 1 | View paper |
| VITEEE 2023 | 2023 | 5 | View paper |
| VITEEE 2022 | 2022 | 1 | View paper |
| VITEEE 2021 | 2021 | 2 | View paper |
Practice every matching question in batches of 20, with every available option.
The non-zero solutions of the equation \(z^2+|z|=0\), where \(z\) is a complex number, are
If \((1+i)(2 i+1)(1+3 i) \ldots(1+n i)=x+i y\), then \(2 \cdot 5 \cdot 10 \ldots\left(1+n^2\right)\) is equal to
The condition in order that \(Z_1, Z_2, Z_3\) are vertices of an isosceles triangle right angled at \(z_2\), is
If \(\alpha\) is a non -real fifth root of unity, then the value of \(3^{\left|1+\alpha+\alpha^2+\alpha^{-2}-\alpha^{-1 \mid}\right|}\), is
If \(x+\frac{1}{x}=1\) and \(p=x^{4000}+\frac{1}{x^{4000}}\) and \(q\) is the digit at unit place in the number \(2^{2 n}+1\), then the value of \((p+q)\) is equal to
If \(\alpha, \beta\) and \(\gamma\) are the cube roots of \(P,(P<0)\), then for any \(x, y\) and \(z\) which does not make denominator zero, the expression \(\frac{x \alpha+y \beta+z \gamma}{x \beta+y \gamma+z \alpha}\) equals to
If \(z_1, z_2\) and \(z_3\) are the vertices \(A, B\) and \(C\) respectively of an isosceles right angled triangle with right angled at \(C\), then \(\left(z_1-z_3^{\prime}\right)\left(z_2-z_3\right)\) equals to
Let \(z_k=\cos \left(\frac{2 k \pi}{10}\right)+i \sin \left(\frac{2 k \pi}{10}\right) ; k=1,2, \ldots \ldots \ldots\) 9, then \(\frac{1}{10}\left\{\left|1-z_1\right|\left|1-z_2\right| \ldots .\left|1-z_a\right|\right\}\) equals to
The complex number $z$ satisfying $z+|z|$ $=1+7 i$, then the value of $|z|^2$ equals