Difficulty distribution
How the classified questions are distributed by difficulty.
Your cart is empty.
Practice Binomial Theorem - Algebra - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
Every graph below is calculated only from this selection.
Year-wise coverage for Binomial Theorem. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| VITEEE 2024 | 2024 | 3 | View paper |
| VITEEE 2023 | 2023 | 2 | View paper |
| VITEEE 2022 | 2022 | 1 | View paper |
| VITEEE 2021 | 2021 | 2 | View paper |
Practice every matching question in batches of 20, with every available option.
Which of the following is the correct principle of Mathematical induction?
The coefficient of the term independent of \(x\) in the expansion \(\left(\frac{x+1}{x^{2 / 3}-x^{1 / 3}+1}-\frac{x-1}{x-x^{1 / 2}}\right)^{10}\) is
If the 2nd, 3rd and 4th terms in the expansion of \((a+b)^n\) be \(240,720\) and 1080 respectively, then the value of \((n, b, a)\) is
Last three digits in \((9)^{50}\) be
If \(x^n=a_0+a_1(1+x)+a_2(1+x)^2+\ldots \ldots \ldots+ a_n(1+x)^n=b_0+b_1(1-x)+b_2(1-x)^2+\ldots . .+ b_n(1-x)^n\), then for \(n=201,\left(a_{101}, b_{101}\right)\) is equal to
If the coefficients of $x^7$ and $x^8$ in the expansion of $\left[2+\frac{x}{3}\right]^n$ are equal, then value of $n$ is
If the coefficient of $x^2$ and $x^3$ in the expansion of $\left(1+8 x+b x^2\right)(1-3 x)^9$ in the power of $x$ are equal, then $b$ is
Coefficient of $x^3$ in the expansion of $\left(x^2-x+1\right)^{10}\left(x^2+1\right)^{15}$ is equal to