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Practice Surface Chemistry - Physical Chemistry - Chemistry previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| JEE Advanced 2026 Paper 2 Online | 2026 | 1 | View paper |
| IIT JEE 2003 | 2003 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
At a given temperature, 0.45 g of acetic acid in 50 mL of water is shaken with 1.0 g of charcoal and the pH of the resulting solution is 3.0 . Assume, the adsorption of acetic acid from the aqueous solution by charcoal follows Freundlich isotherm,
$$\frac{x}{m}=k C^{1 / n}$$
If the plot of $\log _{10}(x / m)$ against $\log _{10} C$ gives a straight line with slope 1 , the value of $k$ in $\mathrm{L} \mathrm{mol}^{-1}$ is $\_\_\_\_$ .
Given: The molar mass of acetic acid is $60 \mathrm{~g} \mathrm{~mol}^{-1}$.
The acid dissociation constant of acetic acid is $1.0 \times 10^{-5}$ at the given temperature.
$x$ is the mass (in grams) of acetic acid adsorbed.
$m$ is the mass (in grams) of charcoal.
$C$ is the equilibrium concentration of acetic acid in the solution after the adsorption is complete.
$k$ and $n$ are constants for acetic acid-charcoal system at the given temperature.