Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Trigonometric Ratios And Identities - Trigonometry - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
Every graph below is calculated only from this selection.
Year-wise coverage for Trigonometric Ratios And Identities. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| BITSAT 2025 | 2025 | 1 | View paper |
| BITSAT 2024 | 2024 | 1 | View paper |
| BITSAT 2023 | 2023 | 3 | View paper |
| BITSAT 2022 | 2022 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
If \(\alpha,\beta,\gamma \in[0,\pi]\) and if \(\alpha,\beta,\gamma\) are in AP, then \({{\sin \alpha - \sin \gamma } \over {\cos \gamma - \cos \alpha }}\) is equal to
A tower \(T_1\) of the height \(60 \mathrm{~m}\) is located exactly opposite to a tower \(T_2\) of height \(80 \mathrm{~m}\) on a straight road. From the top of \(T_1\), if the angle of depression of the foot of \(T_2\) is twice the angle of elevation of the top of \(T_2\), then the width (in \(\mathrm{m}\)) of the road between the feet of the towers \(T_1\) and \(T_2\) is
The upper \((\frac{3}{4})\) th portion of a vertical pole subtends an angel \(\tan ^{-1}\left(\frac{3}{5}\right)\) at a point in the horizontal plane through its foot and at a distance \(40 \mathrm{~m}\) from the foot. A possible height of the vertical is
If \(A, B, C \in[0, \pi]\) and if \(A, B, C\) are in \(\mathrm{AP}\), then \(\frac{\sin A+\sin C}{\cos A+\cos C}\) is equal to
If $A+B=\frac{\pi}{4}$, then $(1+\tan A)(1+\tan B)$ is equal to