Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice 69 Calculus PYQs from BITSAT previous papers (6 years). Ideal for exam prep with clear topic navigation.
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Year-wise coverage for Calculus. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
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Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| BITSAT 2025 | 2025 | 12 | View paper |
| BITSAT 2024 | 2024 | 10 | View paper |
| BITSAT 2023 | 2023 | 10 | View paper |
| BITSAT 2022 | 2022 | 10 | View paper |
| BITSAT 2021 | 2021 | 12 | View paper |
| BITSAT 2020 | 2020 | 15 | View paper |
A varied preview from the papers represented in this selection, with every available option.
Let f(x) = x \(-\) 3, g(x) = 4 \(-\) x. Then the set of values of x for which \(|f(x) + g(x)|\, < \,|f(x)| + |g(x)|\) is true, is given by :
The value of \(\mathop {\lim }\limits_{x \to 0} {{\sqrt {1 - {{\cos x}^2}} } \over {1 - \cos x}}\) is
If g(x) = x2 + x \(-\) 2 and \(\frac{1}{2}gof(x)=2x^2-5x+2\), then f(x) is equal to
The value of \(\lim _\limits{x \rightarrow 0} \frac{8}{x^8}\left(1-\cos \frac{x^2}{2}-\cos \frac{x^2}{4}+\cos \frac{x^2}{2} \cos \frac{x^2}{4}\right)\) is
If $f: X \rightarrow Y$ be a function defined by $f(x)=a \sin \left(x+\frac{\pi}{4}\right)+b \cos x+c$ and $f$ is bijective, then the set $X$ with $\theta=\tan ^{-1}\left(\frac{a+\sqrt{2} b}{a}\right)$ is