Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Three Dimensional Geometry - Algebra - Mathematics previous year questions organised from real papers, with year-wise coverage and clear topic navigation.
Every graph below is calculated only from this selection.
Year-wise coverage for Three Dimensional Geometry. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| BITSAT 2025 | 2025 | 1 | View paper |
| BITSAT 2023 | 2023 | 1 | View paper |
| BITSAT 2022 | 2022 | 1 | View paper |
| BITSAT 2021 | 2021 | 3 | View paper |
| BITSAT 2020 | 2020 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
A line passing through P(3, 7, 1) and R(2, 5, 7) meet the plane 3x + 2y + 11z \(-\) 9 = 0 at Q. Then PQ is equal to
The distance between the line \(r = 2\widehat i - 2\widehat j + 3\widehat k + \lambda (\widehat i - \widehat j + 4\widehat k)\) and the plane \(a\,.\,(\widehat i + 5\widehat j + \widehat k) = 5\) is
Consider the two lines
\({L_1}:{{x + 1} \over 3} = {{y + 2} \over 1} = {{z + 1} \over 2}\) and \({L_2}:{{x - 2} \over 1} = {{y + 2} \over 2} = {{z - 3} \over 3}\)
The unit vector perpendicular to both the lines L1 and L2 is
Angle between the diagonals of a cube is
If the plane \(3x + y + 2z + 6 = 0\) is parallel to the line \({{3x - 1} \over {2b}} = 3 - y = {{z - 1} \over a}\), then the value of \(3a + 3b\) is
The equation of the line passing through \((-4,3,1)\) parallel to the plane \(x+2 y-z-5=0\) and intersecting the line \(\frac{x+1}{-3}=\frac{y-3}{2}=\frac{z-2}{-1}\) is
The magnitude projection of line segment joining points $(1,2,3)$ and $(-1,4,2)$ on the line joining points $(-2,3,3)$ and $(0,6,-3)$ is