Motion In A Straight Line - Physics PYQ (Mechanics)

An object travelling at a speed of 36 km/h comes to rest in a distance of 200 m after the brakes were applied. The retardation produced by the brakes is

A ball is projected upwards. Its acceleration at the highest point is

Which of the following decreases, in motion on a straight line, with constant retardation?

An object is moving with a uniform acceleration which is parallel to its instantaneous direction of motion. The displacement-velocity graph of this object is

The displacement of a particle starting from rest at \(t=0\) is given by \(s=9 t^2-2 t^3\). The time in seconds at which the particle will attain zero velocity is

Two cars A and B are moving with a velocity of 30 km/h in the same direction. They are separated by 10 km. The speed of another car C moving in the opposite direction, if it meets these two cars at an interval of eight minutes is

An object moving along \(X\)-axis with a uniform acceleration has velocity \(\mathbf{v}=\left(12 \mathrm{cms}^{-1}\right) \hat{\mathbf{i}}\) at \(x=3 \mathrm{~cm}\). After 2 s if it is at \(x=-5 \mathrm{~cm}\), then its acceleration is

\(y=\left(P t^2-Q t^3\right) \mathrm{~m}\) is the vertical displacement of a ball which is moving in vertical plane. Then the maximum height that the ball can reach is

A car covers a distance at speed of \(60 \mathrm{~km} \mathrm{~h}^{-1}\). It returns and comes back to the original point moving at a speed of \(v\). If the average speed for the round trip is \(48 \mathrm{~kmh}^{-1}\), then the magnitude of \(v\) is

A student is at a distance 16 m from a bus when the bus begins to move with a constant acceleration of \(9 \mathrm{~m} \mathrm{~s}^{-2}\). The minimum velocity with which the student should run. towards the bus so as the catch it is \(\alpha \sqrt{2} \mathrm{~ms}^{-1}\). The value of \(\alpha\) is

The acceleration of a particle which moves along the positive $X$-axis varies with its position as shown in the figure. If the velocity of the particle is $0.8 \mathrm{~ms}^{-1}$ at $x=0$ , then its velocity at $x=1.4 \mathrm{~m}$ is $\left(\right.$ in $\left.\mathrm{ms}^{-1}\right)$

A particle starts from rest and moves in a straight line. It travels a distance $2 L$ with uniform acceleration and then moves with a constant velocity a further distance of $L$. Finally, it comes to rest after moving a distance of $3 L$ under uniform retardation. Then, the ratio of average speed to the maximum speed $\left(\frac{v}{v_m}\right)$ of the particle is

If a car travels $40 \%$ of the total distance with a speed $v_1$ and the remaining distance with a speed $v_2$, then average speed of the car is