Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Calculus previous year questions for AP EAPCET Mathematics. 26 papers, 624 MCQs — year-wise PYQs for exam practice and mock tests.
Every graph below is calculated only from this selection.
Year-wise coverage for Calculus. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Open a focused page built from the same verified paper data.
Explore previous-paper coverage, trends and focused practice for Indefinite Integration.
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Explore previous-paper coverage, trends and focused practice for Limits Continuity And Differentiability.
Explore previous-paper coverage, trends and focused practice for Definite Integration.
Explore previous-paper coverage, trends and focused practice for Differential Equations.
Explore previous-paper coverage, trends and focused practice for Functions.
Explore previous-paper coverage, trends and focused practice for Differentiation.
Explore previous-paper coverage, trends and focused practice for Area Under The Curves.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| AP EAPCET 2025 21ST MAY EVENING SHIFT | 2025 | 24 | View paper |
| AP EAPCET 2025 21ST MAY MORNING SHIFT | 2025 | 25 | View paper |
| AP EAPCET 2025 22ND MAY EVENING SHIFT | 2025 | 23 | View paper |
| AP EAPCET 2025 22ND MAY MORNING SHIFT | 2025 | 26 | View paper |
| AP EAPCET 2025 23RD MAY EVENING SHIFT | 2025 | 24 | View paper |
| AP EAPCET 2025 23RD MAY MORNING SHIFT | 2025 | 22 | View paper |
| AP EAPCET 2025 24TH MAY MORNING SHIFT | 2025 | 23 | View paper |
| AP EAPCET 2025 26TH MAY EVENING SHIFT | 2025 | 22 | View paper |
| AP EAPCET 2025 26TH MAY MORNING SHIFT | 2025 | 24 | View paper |
| AP EAPCET 2025 27TH MAY MORNING SHIFT | 2025 | 25 | View paper |
| AP EAPCET 2024 18TH MAY MORNING SHIFT | 2024 | 25 | View paper |
| AP EAPCET 2024 19TH MAY EVENING SHIFT | 2024 | 25 | View paper |
| AP EAPCET 2024 20TH MAY EVENING SHIFT | 2024 | 26 | View paper |
| AP EAPCET 2024 20TH MAY MORNING SHIFT | 2024 | 26 | View paper |
| AP EAPCET 2024 21TH MAY EVENING SHIFT | 2024 | 26 | View paper |
| AP EAPCET 2024 21TH MAY MORNING SHIFT | 2024 | 27 | View paper |
| AP EAPCET 2024 22TH MAY EVENING SHIFT | 2024 | 25 | View paper |
| AP EAPCET 2024 22TH MAY MORNING SHIFT | 2024 | 23 | View paper |
| AP EAPCET 2024 23TH MAY MORNING SHIFT | 2024 | 25 | View paper |
| AP EAPCET 2022 4TH JULY EVENING SHIFT | 2022 | 23 | View paper |
| AP EAPCET 2022 4TH JULY MORNING SHIFT | 2022 | 23 | View paper |
| AP EAPCET 2022 5TH JULY MORNING SHIFT | 2022 | 25 | View paper |
| AP EAPCET 2021 19TH AUGUST EVENING SHIFT | 2021 | 21 | View paper |
| AP EAPCET 2021 19TH AUGUST MORNING SHIFT | 2021 | 23 | View paper |
| AP EAPCET 2021 20TH AUGUST EVENING SHIFT | 2021 | 23 | View paper |
| AP EAPCET 2021 20TH AUGUST MORNING SHIFT | 2021 | 20 | View paper |
A varied preview from the papers represented in this selection, with every available option.
If the curves \(\frac{x^2}{a^2}+\frac{y^2}{4}=1\) and \(y^3=16 x\) intersect at right angles, then \(a^2\) is equal to
If the error committed in measuring the radius of a circle is 0.05%, then the corresponding error in calculating its area would be
Find the minimum value of \(2x+3y\), when \(xy=6\).
If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximate error in calculating its surface area.
$$\int_{\pi / 4}^{5 \pi / 4}(|\cos t| \sin t+|\sin t| \cos t) d t=$$
Let \(f: R^{+} \longrightarrow R^{+}\) be a function satisfying \(f(x)-x=\lambda\) (constant), \(\forall x \in R^{+}\) and \(f(x f(y))=f(x y)+x, \forall x, y, \in R^{+}\). Then, \(\lim _\limits{x \rightarrow 0} \frac{(f(x))^{1 / 3}-1}{(f(x))^{1 / 2}-1}=\)