Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice 144 previous year questions (26 papers, 4 years) on Probability - Algebra - Mathematics for AP EAPCET exam mock tests.
Every graph below is calculated only from this selection.
Year-wise coverage for Probability. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
Top subtopics inside this exact selection.
Question coverage for the most populated papers. Every active PYP paper remains listed below.
Newest papers appear first. Sort by year, question coverage or name.
| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| AP EAPCET 2025 21ST MAY EVENING SHIFT | 2025 | 5 | View paper |
| AP EAPCET 2025 21ST MAY MORNING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2025 22ND MAY EVENING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2025 22ND MAY MORNING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2025 23RD MAY EVENING SHIFT | 2025 | 5 | View paper |
| AP EAPCET 2025 23RD MAY MORNING SHIFT | 2025 | 5 | View paper |
| AP EAPCET 2025 24TH MAY MORNING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2025 26TH MAY EVENING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2025 26TH MAY MORNING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2025 27TH MAY MORNING SHIFT | 2025 | 6 | View paper |
| AP EAPCET 2024 18TH MAY MORNING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 19TH MAY EVENING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 20TH MAY EVENING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 20TH MAY MORNING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 21TH MAY EVENING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 21TH MAY MORNING SHIFT | 2024 | 5 | View paper |
| AP EAPCET 2024 22TH MAY EVENING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 22TH MAY MORNING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2024 23TH MAY MORNING SHIFT | 2024 | 6 | View paper |
| AP EAPCET 2022 4TH JULY EVENING SHIFT | 2022 | 6 | View paper |
| AP EAPCET 2022 4TH JULY MORNING SHIFT | 2022 | 6 | View paper |
| AP EAPCET 2022 5TH JULY MORNING SHIFT | 2022 | 6 | View paper |
| AP EAPCET 2021 19TH AUGUST EVENING SHIFT | 2021 | 5 | View paper |
| AP EAPCET 2021 19TH AUGUST MORNING SHIFT | 2021 | 3 | View paper |
| AP EAPCET 2021 20TH AUGUST EVENING SHIFT | 2021 | 4 | View paper |
| AP EAPCET 2021 20TH AUGUST MORNING SHIFT | 2021 | 4 | View paper |
Practice every matching question in batches of 20, with every available option.
P speaks truth in 70% of the cases and Q in 80% of the cases. In what percent of cases are they likely to agree in stating the same fact
A coin is tossed 2020 times. The probability of getting head on 1947th toss is
If \(A\) and \(B\) are two events with \(P(A \cap B)=\frac{1}{3}, P(A \cup B)=\frac{5}{6}\) and \(P\left(A^C\right)=\frac{1}{2}\), then the value of \(P\left(B^C\right)\) is
A discrete random variable X takes values 10, 20, 30 and 40. with probability 0.3, 0.3, 0.2 and 0.2 respectively. Then the expected value of X is
Let \(X\) be a random variable which takes values \(1,2,3,4\) such that \(P(X=r)=K r^3\) where \(r=1,2,3,4\) then
A random variable X has the probability distribution
| X | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
|---|---|---|---|---|---|---|---|---|
| P(X) | 0.15 | 0.23 | 0.12 | 0.10 | 0.20 | 0.08 | 0.07 |
For the events E = {X is a prime number} and F = {X < 4}, then P(E \(\cup\) F) is
12 balls are distributed among 3 boxes, then the probability that the first box will contain 3 balls is
A die is tossed thrice. If event of getting an even number is a success, then the probability of getting at least 2 successes is
A coin is tossed until a head appears or it has been tossed thrice. Given that head doesn’t appear on the first toss, the probability that coin tossed thrice is
Tom and Jerry play a game of alternately throwing an unfair coin. First one to get head wins. If Tom starts the game, he has 62.5% chance of winning the game. Suppose this coin is tossed 5 times, then the probability of getting exactly 3 head is
Box-I contains 3 cards bearing numbers 1, 2, 3 , Box II contains 5 cards bearing numbers 1 , 2, 3, 4, 5 and Box III contains 7 cards bearing numbers 1, 2, 3, 4, 5, 6, 7. One card is drawn at random from each of the boxes. If \(x_i\) be the number on the card drawn from the \(i\) th box, \(i=1,2,3\), then the probability that \(x_1+x_2+x_3\) is odd is equal to
The range of a random variable \(X\) is \(\{1,2,3, \ldots\}\) and \(P(X=x)=\frac{C^x}{x !}\). for \(x=1,2,3\), ... Then, the value of \(C\) is
Nine balls one drawn simultaneously from a bag containing 5 white and 7 black balls. The probability of drawing 3 white and 6 black balls is
The probabilities that \(A\) and \(B\) speak truth are \(\frac{4}{5}\) and \(\frac{3}{4}\) respectively. The probability that they contradict each other when asked to speak on a fact is
One card is selected at random from 27 cards numbered form 1 to 27. What is the probability that the number on the card is even or divisible by 5.
The mean and variance of a binomial variable X are 2 and 1 respectively. The probability that X takes values greater than 1 is
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked randomly. The probability that it is neither red nor green is
Which of the following is not a property of a Binomial distribution?
Five digit numbers are formed by using digits \(1,2,3,4\) and 5 without repetition. Then, the probability that the randomly chosen number is divisible by 4 is
A manager decides to distribute ₹ 20000 between two employees \(X\) and \(Y\). He knows \(X\) deserves more than \(Y\), but does not know how much more. So, he decides to arbitrarily break ₹ 20000 into two parts and give \(X\) the bigger part. Then, the chance that \(X\) gets twice as much as \(Y\) or more is
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