Difficulty distribution
How the classified questions are distributed by difficulty.
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Practice Binomial Theorem PYQ from AP EAPCET: 20 papers, 3 years, 42 multiple-choice questions for algebra exam practice and mock test.
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Year-wise coverage for Binomial Theorem. Each bar uses a separate theme-derived color.
How the classified questions are distributed by difficulty.
MCQ, numerical, multiple-select and other formats found in these papers.
Top subjects by unique question coverage.
Top topics across the included previous year papers.
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Question coverage for the most populated papers. Every active PYP paper remains listed below.
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| Paper | Year / session | Questions in this view | Open |
|---|---|---|---|
| AP EAPCET 2025 21ST MAY EVENING SHIFT | 2025 | 3 | View paper |
| AP EAPCET 2025 21ST MAY MORNING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 22ND MAY EVENING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 22ND MAY MORNING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 23RD MAY EVENING SHIFT | 2025 | 3 | View paper |
| AP EAPCET 2025 23RD MAY MORNING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 24TH MAY MORNING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 26TH MAY EVENING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 26TH MAY MORNING SHIFT | 2025 | 2 | View paper |
| AP EAPCET 2025 27TH MAY MORNING SHIFT | 2025 | 4 | View paper |
| AP EAPCET 2024 18TH MAY MORNING SHIFT | 2024 | 3 | View paper |
| AP EAPCET 2024 19TH MAY EVENING SHIFT | 2024 | 1 | View paper |
| AP EAPCET 2024 20TH MAY EVENING SHIFT | 2024 | 2 | View paper |
| AP EAPCET 2024 20TH MAY MORNING SHIFT | 2024 | 1 | View paper |
| AP EAPCET 2024 21TH MAY EVENING SHIFT | 2024 | 1 | View paper |
| AP EAPCET 2024 21TH MAY MORNING SHIFT | 2024 | 2 | View paper |
| AP EAPCET 2024 22TH MAY EVENING SHIFT | 2024 | 3 | View paper |
| AP EAPCET 2024 22TH MAY MORNING SHIFT | 2024 | 2 | View paper |
| AP EAPCET 2024 23TH MAY MORNING SHIFT | 2024 | 2 | View paper |
| AP EAPCET 2022 4TH JULY EVENING SHIFT | 2022 | 1 | View paper |
Practice every matching question in batches of 20, with every available option.
The least value of \(n\) so that \({ }^{(n-1)} C_3+{ }^{(n-1)} C_4>{ }^n C_3\)
If the coefficients of $r$ th, $(r+1)$ th and $(r+2)$ th terms in the expansion of $(1+x)^n$ are in the ratio of $4: 15: 42$, then $n-r$ is equal to
If the coefficients of $(2 r+6)$ th and $(r-1)$ th terms in the expansion of $(1+x)^{21}$ are equal, then the value of $r$ is equal to
If $(1+x)^n=\sum_{r=0}^n C, x^r$, then the value of $C_0+\left(C_0+C_1\right)+\left(C_0+C_1+C_2\right)+\ldots+ \left(C_0+C_1+C_2+\ldots+C_n\right)$ is
If $x$ is so large that terms containing $x^{-3}, x^{-4}, x^{-5}, \ldots$ can be neglected, then the approximate value of $\left(\frac{3 x-5}{4 x^2+3}\right)^{-1 / 5}$ is
Showing 20 of 42 questions