Carboxylic Acids & Derivatives - Organic Chemistry PYQ

The correct order of acidic strength among the following is

An aryl carboxylic acid on treatment with sodium hydrogen carbonate liberates a gaseous molecule. Identify the gas molecule liberated.

In the presence of peroxide, styrene reacts with HBr to give \(X\). When \(X\) is reacted with magnesium in dry ether followed by \(\mathrm{CO}_2\) and hydrolysis gave \(Y\). Treatment of Y with \(\mathrm{PCl}_5\) and then next with \(\mathrm{H}_2\). \(\mathrm{Pd}-\mathrm{BaSO}_4\) gave Z . What is Z ?

What are $A$ and $B$ in the following reaction sequence ?

$$\mathrm{CH}_3 \mathrm{COOH} \xrightarrow{A} X \xrightarrow[\mathrm{H}^{+}]{Y} B \text { (Analgesic drug) }$$

$$\text { Benzamide } \xrightarrow{\mathrm{Br}_2 / \mathrm{NaOH}} X \xrightarrow[\text { Alc. } \mathrm{KOH}]{\mathrm{CHCl}_3} Y$$

The conversion of $X$ to $Y$ is

What are $X$ and $Y$ respectively in the following reactions?

In the reaction sequence $Y$ is

$$\mathrm{CH}_3 \mathrm{CO}_2 \mathrm{H} \xrightarrow[(2) \Delta]{(1) \mathrm{NH}_3} P \xrightarrow{\mathrm{Br} / \mathrm{NaOH}} Y$$

Assertion (A) : Carboxylic acids are more acidic than phenols

Reason (R) : Resonance structures of carboxylate ion are equivalent, while resonance structures of phenoxide ion are not equivalent.

Consider the following reactions

$Y$ can not be obtained from which of the following reaction?

Arrange the products I, II, III from the following reactions in decreasing order of their acid strength.

$$\text { The most acidic carboxylic acid is }$$

What are $X, Y, Z$ in the following reaction sequence?

But-2-ene $\xrightarrow{X}$ Ethanoic acid $\xrightarrow{Y}$ Ethanoyl chloride $\xrightarrow[\text { Anhy. } \mathrm{AlCl}_3]{\text { Benzene }} Z$

What are $X$ and $Y$ respectively in the following set of reactions?

An alkyl bromide $X\left(\mathrm{C}_5 \mathrm{H}_{11} \mathrm{Br}\right)$ undergoes hydrolysis in a two step mechanism $X$ is converted to Grignard reagent and then reacted with $\mathrm{CO}_2$ in dry ether followed by acidification gave $Y$. What is $Y$ ?

Consider the following sequence of reactions

$$\mathrm{C}_6 \mathrm{H}_5 \mathrm{COONa} \xrightarrow[\Delta]{\mathrm{NaOH} / \mathrm{CaO}} X \xrightarrow[\text { Anhy } \cdot \mathrm{AlCl}_3]{\text { CO+ } \mathrm{HCl}} Y \xrightarrow[\text { NaOH }]{\text { Conc. }} A+B$$

If $A$ is the reduction product of $Y$, what is $B$ ?

$$\text { The final product }(C) \text { in the given reaction sequence is }$$

$$\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH} \xrightarrow{\mathrm{SOCl}_2}(A) \xrightarrow[\text { anhy } \cdot \mathrm{AlCl}_3]{\mathrm{C}_6 \mathrm{H}_6}(B) \xrightarrow[\text { (ii) } \mathrm{KOH}_4 /\left(\mathrm{CH}_2 \mathrm{OH}\right)_2]{\text { (i) } \mathrm{NH}_2-\mathrm{NH}_2}(C)$$