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JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
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Questions
75
Duration
180 mins
Package
IIT-JEE Main - Previous Year Papers
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Subtopic distribution
Difficulty distribution
75questions
Medium
61
81.3%
Easy
12
16%
Hard
2
2.7%
Question type distribution
75questions
Multiple Choices
60
80%
Numerical Answer Type (NAT)
15
20%
Syllabus
Full Syllabus
Sample questions from this paper
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2026 · Chemistry · Physical Chemistry · Ionic Equilibrium
JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
The first and second ionization constants of H2X are $2.5 \times 10^{-8}$ and $1.0 \times 10^{-13}$ respectively.
The concentration of ${X^{2-}}$ in $0.1\ \mathrm{M}$ H2X solution is ______ $\times 10^{-15}\ \mathrm{M}$. (Nearest Integer)
Enter a numerical response
2026 · Physics · Mechanics · Heat And Thermodynamics
JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
A diatomic gas $(\gamma=1.4)$ does 100 J of work when it is expanded isobarically. Then the heat given to the gas $\_\_\_\_$ J.
Enter a numerical response
2026 · Mathematics · Trigonometry · Inverse Trigonometric Functions
JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
Let the maximum value of $\left(\sin ^{-1} x\right)^2+\left(\cos ^{-1} x\right)^2$ for $x \in\left[-\frac{\sqrt{3}}{2}, \frac{1}{\sqrt{2}}\right]$ be $\frac{\mathrm{m}}{\mathrm{n}} \pi^2$, where $\operatorname{gcd}(\mathrm{m}, \mathrm{n})=1$. Then $\mathrm{m}+\mathrm{n}$ is equal to $\_\_\_\_$。
Enter a numerical response
2026 · Chemistry · Physical Chemistry · Solutions
JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
The osmotic pressure of a living cell is 12 atm at 300 K. The strength of sodium chloride solution that is isotonic with the living cell at this temperature is ________ g L-1. (Nearest integer)
Given : R = 0.08 L atm K-1 mol-1
Assume complete dissociation of NaCl
(Given: Molar mass of Na and Cl are 23 and 35.5 g mol-1 respectively.)
Enter a numerical response
2026 · Physics · Modern Physics · Dual Nature Of Radiation
JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
A particle having electric charge $3 \times 10^{-19} \mathrm{C}$ and mass $6 \times 10^{-27} \mathrm{~kg}$ is accelerated by applying an electric potential of 1.21 V .
Wavelength of the matter wave associated with the particle is $\alpha \times 10^{-12} \mathrm{~m}$. The value of $\alpha$ is $\_\_\_\_$ .
(Take Planck's constant $=6.6 \times 10^{-34} \mathrm{~J} . \mathrm{s}$ )
Wavelength of the matter wave associated with the particle is $\alpha \times 10^{-12} \mathrm{~m}$. The value of $\alpha$ is $\_\_\_\_$ .
(Take Planck's constant $=6.6 \times 10^{-34} \mathrm{~J} . \mathrm{s}$ )
Enter a numerical response
2026 · Mathematics · Algebra · Binomial Theorem
JEE MAIN 2026 ONLINE 21ST JANUARY EVENING SHIFT
If $\left(\frac{1}{{ }^{15} \mathrm{C}_0}+\frac{1}{{ }^{15} \mathrm{C}_1}\right)\left(\frac{1}{{ }^{15} \mathrm{C}_1}+\frac{1}{{ }^{15} \mathrm{C}_2}\right) \ldots\left(\frac{1}{{ }^{15} \mathrm{C}_{12}}+\frac{1}{{ }^{15} \mathrm{C}_{13}}\right)=\frac{\alpha^{13}}{{ }^{14} \mathrm{C}_0{ }^{14} \mathrm{C}_1 \cdots{ }^{14} \mathrm{C}_{12}}$, then $30 \alpha$ is equal to
$\_\_\_\_$ .
Enter a numerical response