JEE MAIN 2023 ONLINE 10TH APRIL EVENING SHIFT
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The half life of a radioactive substance is T. The time taken, for disintegrating \(\frac{7}{8}\)th part of its original mass will be:
Ferric chloride is applied to stop bleeding because -
If \(\mathrm{S}_{n}=4+11+21+34+50+\ldots\) to \(n\) terms, then \(\frac{1}{60}\left(\mathrm{~S}_{29}-\mathrm{S}_{9}\right)\) is equal to :
A message signal of frequency \(3 ~\mathrm{kHz}\) is used to modulate a carrier signal of frequency \(1.5 ~\mathrm{MHz}\). The bandwidth of the amplitude modulated wave is
Gibbs energy vs T plot for the formation of oxides is given below.

For the given diagram, the correct statement is -
Let the line \(\frac{x}{1}=\frac{6-y}{2}=\frac{z+8}{5}\) intersect the lines \(\frac{x-5}{4}=\frac{y-7}{3}=\frac{z+2}{1}\) and \(\frac{x+3}{6}=\frac{3-y}{3}=\frac{z-6}{1}\) at the points \(\mathrm{A}\) and \(\mathrm{B}\) respectively. Then the distance of the mid-point of the line segment \(\mathrm{AB}\) from the plane \(2 x-2 y+z=14\) is :