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Exam Details

Electronics & Communication Engineering (EC) 2013 [Session 4]

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Questions 65
Duration 180 mins
Package Electronics & Communication Engineering (EC) - Previous Year Papers

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Subject distribution

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Topic distribution

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Subtopic distribution

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Difficulty distribution

Easy 65 100%

Question type distribution

Multiple Choices 65 100%

Instructions

Electronics & Communication Engineering (EC) 2013 [Session 4] – Instructions
  • Total number of questions: 65
  • 30 questions carry one mark each
  • 35 questions carry two marks each
  • Negative marking: 1/3 of the marks allotted to the question
  • Use of calculator is allowed
  • This is a proctored examination
  • All other browser applications will be automatically closed
  • After three warnings, the examination window will close automatically

Syllabus

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Sample questions from this paper

Questions are selected across the paper subjects wherever the paper contains that variety.

1
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 4]
Q.1 – Q.25 carry one mark each.

Let g(t) = e−πt2, and h(t) is a filter matched to g(t). If g(t) is applied as input to h(t), then the Fourier transform of the output is

A
e⁻π²
B
e⁻π²/2
C
e⁻π/2
D
e⁻2π²
2
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 4]

The return loss of a device is found to be 20 dB. The voltage standing wave ratio (VSWR) and magnitude of reflection coefficient are respectively

A
1.22 and 0.1
B
0.81 and 0.1
C
−1.22 and 0.1
D
2.44 and 0.2
3
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 4]

A source vs(t) = V cos 100πt has an internal impedance of (4 + j3) Ω. If a purely resistive load connected to this source has to extract the maximum power out of the source, its value in Ω should be

A
3
B
4
C
5
D
7
4
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 4]

The transfer function V2(s)/V1(s) of the circuit shown below is

A
0.5s + 1 / s + 1
B
3s + 6 / s + 2
C
s + 2 / s + 1
D
s + 1 / s + 2
5
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 4]

Assuming zero initial condition, the response y(t) of the system given below to a unit step input u(t) is

A
u(t)
B
t u(t)
C
t²/2 u(t)
D
eᵗ u(t)
6
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 4]

A polynomial f(x) = a5x5 + a4x4 + a3x3 + a2x2 + a1x + a0, with all coefficients positive has

A
no real roots
B
no negative real root
C
odd number of real roots
D
at least one positive and one negative real root