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Exam Details

Electronics & Communication Engineering (EC) 2013 [Session 1]

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Questions 65
Duration 180 mins
Package Electronics & Communication Engineering (EC) - Previous Year Papers

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Subject distribution

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Difficulty distribution

Easy 65 100%

Question type distribution

Multiple Choices 65 100%

Instructions

Electronics & Communication Engineering (EC) 2013 [Session 1] – Instructions
  • Total number of questions: 65
  • 30 questions carry one mark each
  • 35 questions carry two marks each
  • Negative marking: 1/3 of the marks allotted to the question
  • Use of calculator is allowed
  • This is a proctored examination
  • All other browser applications will be automatically closed
  • After three warnings, the examination window will close automatically

Syllabus

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Sample questions from this paper

Questions are selected across the paper subjects wherever the paper contains that variety.

1
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 1]
Q.1 – Q.25 carry one mark each.

A bulb in a staircase has two switches, one switch being at the ground floor and the other one at the first floor. The bulb can be turned ON and also can be turned OFF by any one of the switches irrespective of the state of the other switch. The logic of switching of the bulb resembles

A
an AND gate
B
an OR gate
C
an XOR gate
D
a NAND gate
2
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 1]

Consider a vector field A⃗ (r). The closed loop line integral ∮A⃗ ⋅dl⃗ can be expressed as

A
∬(∇×A⃗ )⋅d⃗s over the closed surface bounded by the loop
B
∭(∇⋅A⃗ )dV over the closed volume bounded by the loop
C
∭(∇⋅A⃗ )dV over the open volume bounded by the loop
D
∬(∇×A⃗ )⋅d⃗s over the open surface bounded by the loop
3
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 1]

Two systems with impulse responses h1(t) and h2(t) are connected in cascade. Then the overall impulse response of the cascaded system is given by

A
product of h₁(t) and h₂(t)
B
sum of h₁(t) and h₂(t)
C
convolution of h₁(t) and h₂(t)
D
subtraction of h₂(t) from h₁(t)
4
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 1]

In a forward biased pn junction diode, the sequence of events that best describes the mechanism of current flow is

A
injection, and subsequent diffusion and recombination of minority carriers
B
injection, and subsequent drift and generation of minority carriers
C
extraction, and subsequent diffusion and generation of minority carriers
D
extraction, and subsequent drift and recombination of minority carriers
5
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 1]

In IC technology, dry oxidation (using dry oxygen) as compared to wet oxidation (using steam or water vapor) produces

A
superior quality oxide with a higher growth rate
B
inferior quality oxide with a higher growth rate
C
inferior quality oxide with a lower growth rate
D
superior quality oxide with a lower growth rate
6
2013 · Unclassified
Electronics & Communication Engineering (EC) 2013 [Session 1]

The maximum value of θ until which the approximation sinθ ≈ θ holds to within 10% error is

A
10°
B
18°
C
50°
D
90°