Exam Details
AIEEE 2012
Review the key details, then start the test when you are ready. You can also open the full package to see related papers.
Questions
89
Duration
180 mins
Package
IIT-JEE Main - Previous Year Papers
Paper pattern & analysis
Filter this paper by subject, topic or subtopic. Every graph updates from the selected questions.
Topic distribution
Subtopic distribution
Difficulty distribution
89questions
Medium
47
52.8%
Easy
42
47.2%
Question type distribution
89questions
Multiple Choices
89
100%
Syllabus
Full Syllabus
Sample questions from this paper
Questions are selected across the paper subjects wherever the paper contains that variety.
2012 · Physics · Mechanics · Properties Of Matter
AIEEE 2012
A liquid in a beaker has temperature \(\theta \left( t \right)\) at time \(t\) and \({\theta _0}\) is temperature of surroundings, then according to Newton's law of cooling the correct graph between \({\log _e}\left( {\theta - {\theta _0}} \right)\) and \(t\) is :
A
B
C
D
2012 · Chemistry · Physical Chemistry · Gaseous State
AIEEE 2012
The compressibility factor for a real gas at high pressure is :
2012 · Mathematics · Algebra · Sequences And Series
AIEEE 2012
Statement-1: The sum of the series 1 + (1 + 2 + 4) + (4 + 6 + 9) + (9 + 12 + 16) +.....+ (361 + 380 + 400) is 8000.
Statement-2: \(\sum\limits_{k = 1}^n {\left( {{k^3} - {{(k - 1)}^3}} \right)} = {n^3}\), for any natural number n.
2012 · Physics · Mechanics · Heat And Thermodynamics
AIEEE 2012
A Carnot engine, whose efficiency is \(40\%\), takes in heat from a source maintained at a temperature of \(500\) \(K.\) It is desired to have an engine of efficiency \(60\% .\) Then, the intake temperature for the same exhaust (sink) temperature must be :
2012 · Chemistry · Physical Chemistry · Solid State
AIEEE 2012
Lithium forms body centred cubic structure. The length of the side of its unit cell is 351 pm. Atomic radius
of the lithium will be :
2012 · Mathematics · Algebra · Matrices And Determinants
AIEEE 2012
Let \(P\) and \(Q\) be \(3 \times 3\) matrices \(P \ne Q.\) If \({P^3} = {Q^3}\) and
\({P^2}Q = {Q^2}P\) then determinant of \(\left( {{P^2} + {Q^2}} \right)\) is equal to :
\({P^2}Q = {Q^2}P\) then determinant of \(\left( {{P^2} + {Q^2}} \right)\) is equal to :